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3 years ago

5

Whitch is the equation of a line that is perpendicular to the lone represented by

1 answer:

Anon25 [30]3 years ago

8 0

It would be the second one because to make a equation perpendicular, you have to flip the fraction (and if it was a whole number like 6 it would become 1/6) and then make it negative.
So your new equation would be y=-6/7x+4

You might be interested in

Slope = 6 , through = (4,13)

alukav5142 [94]

Answer:

y=6x-11

Step-by-step explanation:

I think sorry if I am wrong but u didnt ask u just put that

6 0

2 years ago

If 9x²+Px+25 is a perfect square, then find the value of P

kvv77 [185]

30 is the value of P
Steps:
A perfect square follows the pattern $a^2+2ab+b^2\\\boxed{a=3,b=5}\\\boxed{2ab=30}$

8 0

3 years ago

Read 2 more answers

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago

2x -3y =2<br><br> x = 6y - 5

never [62]

2(6y - 5) - 3y = 2
12y - 10 - 3y = 2
9y - 10 = 2
9y = 12
y = 4/3, or 1 1/3
2x - 3(4/3) = 2
2x - 12/3 = 2
2x - 4 = 2
2x = 6
x = 3

7 0

2 years ago

What point is found by going 1 space to the right and then 5 spaces up?

tensa zangetsu [6.8K]

1, 5
Should be correct

8 0

2 years ago