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Strike441 [17]
2 years ago
14

4. Write an equation of the ellipse with foci at (±1, 0) and co-vertices at (0, ±2)

Mathematics
1 answer:
aev [14]2 years ago
4 0

Answer:

Step-by-step explanation:

The foci:

F=(1,0)

F'=(-1,0)

The co-vertices:

V=(0,2

V'=(-2,0)

\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1\\\\with\ \\b=2\\and \\2*a=2*|FV|=2*\sqrt{5} \, a=\sqrt{5}\\\\\dfrac{x^2}{5} +\dfrac{y^2}{4} =1\\

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Vitek1552 [10]

Answer:

1. $33.00

2. $48.00

3. $3.00

4. $36.40

Step-by-step explanation:

44.00 - 25% = 33 —> $33.00

80.00 - 40% = 48 —> $48.00

9.99 - 70% = 2.997 —> (round the 7 up because it's above 5) $3.00

52.00 - 30% = 36.4 —> $36.40

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2 years ago
Can some help me answer this question ASAP
Maru [420]

Answer:

A

Step-by-step explanation:

v + w   //substitute values

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-7i +2

4 0
2 years ago
The cone shown below has a slant height of 15 centimeters and a height of 12 centimeters. What is the volume of the cone? A 113.
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Answer:

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Step-by-step explanation:

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2 years ago
Find the missing terms in each of the ​
zubka84 [21]
1.29,31
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8 0
2 years ago
A waste management company is designing a rectangular construction dumpster that will be twice as long as it is wide and must ho
photoshop1234 [79]

Answer:

The dimensions that minimize the surface are:

Wide: 1.65 yd

Long: 3.30 yd

Height: 2.20 yd

Step-by-step explanation:

We have a rectangular base, that its twice as long as it is wide.

It must hold 12 yd^3 of debris.

We have to minimize the surface area, subjet to the restriction of volume (12 yd^3).

The surface is equal to:

S=2(w*h+w*2w+2wh)=2(3wh+2w^2)

The volume restriction is:

V=w*2w*h=2w^2h=12\\\\h=\frac{6}{w^2}

If we replace h in the surface equation, we have:

S=2(3wh+2w^2)=6w(\frac{6}{w^2})+4w^2=36w^{-1}+4w^2

To optimize, we derive and equal to zero:

dS/dw=36(-1)w^{-2} + 8w=0\\\\36w^{-2}=8w\\\\w^3=36/8=4.5\\\\w=\sqrt[3]{4.5} =1.65

Then, the height h is:

h=6/w^2=6/(1.65^2)=6/2.7225=2.2

The dimensions that minimize the surface are:

Wide: 1.65 yd

Long: 3.30 yd

Height: 2.20 yd

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3 years ago
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