Answer:
1. $33.00
2. $48.00
3. $3.00
4. $36.40
Step-by-step explanation:
44.00 - 25% = 33 —> $33.00
80.00 - 40% = 48 —> $48.00
9.99 - 70% = 2.997 —> (round the 7 up because it's above 5) $3.00
52.00 - 30% = 36.4 —> $36.40
Answer:
A
Step-by-step explanation:
v + w //substitute values
-3i + 2 - 4i //combine like terms
-7i +2
Answer:
it should be C.188.4
Step-by-step explanation:
i hope it helps :) <3
1.29,31
2.42,47
3.81,69
4.50,36
5.7,16
6.26,30
7.15,23
8.28,34
Answer:
The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd
Step-by-step explanation:
We have a rectangular base, that its twice as long as it is wide.
It must hold 12 yd^3 of debris.
We have to minimize the surface area, subjet to the restriction of volume (12 yd^3).
The surface is equal to:

The volume restriction is:

If we replace h in the surface equation, we have:

To optimize, we derive and equal to zero:
![dS/dw=36(-1)w^{-2} + 8w=0\\\\36w^{-2}=8w\\\\w^3=36/8=4.5\\\\w=\sqrt[3]{4.5} =1.65](https://tex.z-dn.net/?f=dS%2Fdw%3D36%28-1%29w%5E%7B-2%7D%20%2B%208w%3D0%5C%5C%5C%5C36w%5E%7B-2%7D%3D8w%5C%5C%5C%5Cw%5E3%3D36%2F8%3D4.5%5C%5C%5C%5Cw%3D%5Csqrt%5B3%5D%7B4.5%7D%20%3D1.65)
Then, the height h is:

The dimensions that minimize the surface are:
Wide: 1.65 yd
Long: 3.30 yd
Height: 2.20 yd