1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pentagon [3]
3 years ago
15

The diameter of the circle is 8 inches. What is the area?

Mathematics
2 answers:
EleoNora [17]3 years ago
8 0

50.2655 but You can also put it as 50in! :D

bagirrra123 [75]3 years ago
3 0

50.3in² ( to 1 decimal place )

the area of a circle is calculated using

area = πr² ( where r is the radius)

here diameter = 8 ⇒ r =8/2 = 4

area = π × 4² = 16π = 50.3 in²



You might be interested in
An exponential function f(x) is reflected across the x-axis to create the function g(x). Which is a true statement regarding f(x
valentina_108 [34]
That would be the last choice.  Opposite meaning different sign
4 0
3 years ago
Read 2 more answers
Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

8 0
2 years ago
A washer and a dryer cost $552 combined. The washer costs $98 less than the dryer. What is the cost of the dryer?
Sedaia [141]

552-98 = 450

454/2 = 227

washer cost $227

 227+98 = 325

dryer cost $325

 

5 0
3 years ago
Original price $18 and percent of discount is 65% what is the sale price
liq [111]

Answer:

$6.3

Step-by-step explanation:

Original price = $18

Percentage Discount = 65%

Discount = 18*65% = 18*0.65 = $11.7

Sale Price = Original price - Discount

= $18 - $11.7

= $6.3

7 0
2 years ago
4 2/3 + 1 3/4 give your answer as a mixed number
Anna71 [15]

Answer:

6 5/12

Step-by-step explanation:

Given the expression :

4 2/3 + 1 3/4

The sum of the numbers :

4 2/3 + 1 3/4

14/3 + 7/4

L.C.M of 3 and 4 = 12

(56 + 21) / 12

77 / 12

= 6 5/12

7 0
3 years ago
Other questions:
  • Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?
    6·2 answers
  • Mike grew 7 carrots but the rabbits ate 6 carrots how many carrots does mike have left
    6·1 answer
  • GET 35 POINTS! I need help with these 3 questions!!
    6·1 answer
  • verizon charges $35 flat fee for unlimited calling plus $0.30 per text message. Dennis was charged $78.80 in February. How many
    5·2 answers
  • Y2 + 8zx - 2xy -4yz factorise ?
    6·1 answer
  • How do I find the length of the legs of an isosceles right triangle if i only know the length of the hypotenuse?
    6·1 answer
  • Arrange the expression in increasing order of their values
    10·1 answer
  • As part of the underwriting process for insurance, each prospective policyholder is tested for high blood pressure. Let X repres
    7·1 answer
  • The equation y minus 3 = negative 2 (x + 5) is written in point-slope form. What is the y-intercept of the line?
    6·2 answers
  • plz, help I will give you the brainiest How likely is it to get a red card? A heart? A red or black card? A 2 of Hearts? Use the
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!