This is a statistics problem on permutation and combination. To differentiate this, permutation involves on the arrangement in which order doesn't matter. For combination, order matters.
For example, if you arrange A, B and C, for permutation it could be AB, BA, CA, AC, BC and CB. But for combination, it would just be AB, AC and BC.
So, in this problem where he is asked to arrange 8 jars in which order doesn't matter. It is permutation. You can solve this just by calculator. The formula would be nPr, where n is the total number of items while r is the number of items to be sorted. Thus,
nPr = 10P8 = 1, 814,400
Thus, the answer is B.
7 + z < 3
You solve this the same way you would any other algebraic expression such as..
7 + x = 3.
So, just subtract the seven from the three and you have your answer!
7 + z < 3
7 + z - 7 < 3 - 7
z < -4
Answer:
its the frist one (The ratio 9 to 12 is greater than 4 to 6.)
Step-by-step explanation:
