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spin [16.1K]
3 years ago
5

For each point, identify the axis or quadrant where the point is located.

Mathematics
1 answer:
natka813 [3]3 years ago
6 0
(0,6) is on the y-axis. (5,-2) is on the 4th quadrant. (-1,10) is on the 2nd quadrant. (-1/4, -6*1/2) is on the 3rd quadrant. (5,0) is on the x axis. (8.7,2.3) is on the 1rst quadrant
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If f(n) = (2n + 3)2 – 2n, which statement is true?
viktelen [127]

Answer: f(5) = 16

Step-by-step explanation:

f(n) = (2n + 3)2 – 2n

f(5) = ((2 x 5) + 3)2 – 2 x 5

f(5) = (10 + 3)2 – 10

f(5) = (13)2 – 10

f(5) = 26 – 10

f(5) = 16

5 0
3 years ago
What is the initial value in the function 2x + 3y = 6?
Galina-37 [17]

THE INITIAL VALUE IN THE FUNCTION ARE X=0 AND Y=2 OR X=3 AND Y=0.

Step-by-step explanation:

The initial value of the line segment is the value at which X=0 .

X=0 means nothing but a Y-intercept.

Now set X=0, in the function 2x+3y=6

2(0)+3y=6.

3y=6.

Therefore Y=2

so (0,2) is one point on the graph or line segment.

similarly considering X=3 in the line segment and that means Y=0.

Y=0 indicates X-intercept.

substituting X=3 in the function

2(X)+3(0)=6

2X=6

Therefore X=3

so (3,0) is another point on the line segment or graph.

4 0
3 years ago
Question 6 of 10
cluponka [151]
The answer at least i think is a
8 0
2 years ago
150 divided by 10% pls :)
vlabodo [156]

Answer:

1500

Step-by-step explanation:

i typed it into a calculator

5 0
3 years ago
Resolve into factors:- 9x4 + 2x²y²+ y4​
makvit [3.9K]

Answer:

(3x^2+y^2+2xy)(3x^2+y^2-2xy)

Step-by-step explanation:

9x^4+2x^2y^2+y^4

(3x^2+y^2+2xy)(3x^2+y^2-2xy)

Both terms are perfect squares. So you will factor using the difference of squares formula. a^2-b^2=(a+b)(a-b)

Take what the square is for every term.

9x^4. What squared is 9? 3 and take half of the power or 2. That's how you get the 3x^2

2x^2y^2 is the same way. 2xy and 2xy

y^4 is y but dived he powers by 2 to get y^2.

Take one of each and but in () like I have above.

4 0
3 years ago
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