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2 years ago

5

For each point, identify the axis or quadrant where the point is located.

1 answer:

natka813 [3]2 years ago

6 0

(0,6) is on the y-axis. (5,-2) is on the 4th quadrant. (-1,10) is on the 2nd quadrant. (-1/4, -6*1/2) is on the 3rd quadrant. (5,0) is on the x axis. (8.7,2.3) is on the 1rst quadrant

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Express in the form 1 : n 4 : 12

Vesna [10]

Answer:

1:3

Step-by-step explanation:

4:12 divides by 4 to give

1 : 3

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2 years ago

Read 2 more answers

Firdavs [7]

Answer:

(–10, –2), (6, 6)

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

<u><em>Verify each case</em></u>

case 1) (5, –4), (–2, 1)

substitute in the formula

$m=\frac{1-(-4)}{-2-5}$

$m=\frac{1+4}{-2-5}$

$m=\frac{5}{-7}$

$m=-\frac{5}{7}$ ----> the slope is negative

case 2) (6, –10), (2, 10)

substitute in the formula

$m=\frac{10-(-10)}{2-6}$

$m=\frac{10+10}{2-6}$

$m=\frac{20}{-4}$

$m=-5$ ----> the slope is negative

case 3) (–10, –2), (6, 6)

substitute in the formula

$m=\frac{6-(-2)}{6-(-10)}$

$m=\frac{6+2}{6+10}$

$m=\frac{8}{16}$

$m=0.5$ ----> the slope is positive

case 4) (5, –1), (–6, 6)

substitute in the formula

$m=\frac{6-(-1)}{-6-5}$

$m=\frac{6+1}{-6-5}$

$m=\frac{7}{-11}$

$m=-\frac{7}{11}$ ----> the slope is negative

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2 years ago

PLEASE HELPPP!! i need the answer quick please!

Temka [501]

Answer:

80

Step-by-step explanation:

Use the equation 180-(70 +30)

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2 years ago

A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?

DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals $2.20\times 10^{8}\,Pa$ . The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress ( $\sigma$ ), measured in pascals, in the wire with circular cross-section is:

$\sigma = \frac{4\cdot F}{\pi\cdot D^{2}}$ (1)

Where:

$F$ - Axial force, measured in newtons.

$D$ - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that $F = 800\,N$ and $D = 0.002\,m$ , then the axial stress experimented by the titanium wire is:

$\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}$

$\sigma \approx 2.546\times 10^{8}\,Pa$

Since stress is greater than ultimate strength, the wire will break.

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2 years ago

If a matrix does NOT have an inverse, what do you know about the determinant?

Strike441 [17]

Here is your answer!

B) The determinent is 0

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