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2 years ago

For each point, identify the axis or quadrant where the point is located.

Mathematics

1 answer:

natka813 [3]2 years ago

6 0

(0,6) is on the y-axis. (5,-2) is on the 4th quadrant. (-1,10) is on the 2nd quadrant. (-1/4, -6*1/2) is on the 3rd quadrant. (5,0) is on the x axis. (8.7,2.3) is on the 1rst quadrant

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The means and mean absolute deviations of the individual times of members on two 4 times 400 meter relay track teams are shown i

Yakvenalex [24]

The correct answer is option C which is the ratio of the difference in the means of the two teams to the mean absolute deviation of Team B will be 0.25.

Mean is defined as the ratio of the sum of the number of the data sets to the total number of the data.

The difference between the mean times is about 16 times the mean absolute deviation of the data set.

59.32 - 59.1 = 0.22

2.4 - 1.5 = 0.9

0.22 / 0.9 = 0.25

Therefore the correct answer is option C which is the ratio of the difference in the means of the two teams to the mean absolute deviation of Team B will be 0.25.

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1 year ago

8/1 ÷ 1/4 what's the result?

jonny [76]

The correct answer is 32

3 0

3 years ago

Read 2 more answers

CHECK ANSWERS -

Tju [1.3M]

Both are correct.

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6 0

3 years ago

F(x)=14-2x<br> If f(x)=20, find x

mixer [17]

Answer:

x= -3

Step-by-step explanation:

20=14-2x

-14 -14

6 = -2x

÷-2 ÷-2

-3 =x

3 0

2 years ago

Read 2 more answers

classify each angle pair using all the names that apply using the diagram on the left , answering 1 2 3 4 and 5 , explain why.(

vredina [299]

Answer:

see the attachment

Step-by-step explanation:

1. Two angles that sum to 90° are <em>complementary</em>, whether they are adjacent or not. Angles LMN and NMP are also <em>adjacent</em>.

2. Vertical angles created by two distinct lines are <em>never adjacent</em>. The sides of the angles are created by the same lines, and the angles share a vertex, but there is no ray that is a side common to both angles.

3. Angle GMK is supplementary to angle JMG.

4. Vertical angles are congruent. See question 2.

5. See question 1.

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3 years ago