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Svet_ta [14]
3 years ago
6

Complete this equation ​

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

(x-3)^2+(y-2)^2=3

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Hillel is juggling flaming torches to raise money for charity. His initial appearence raises $500, and he raises $15 for each mi
7nadin3 [17]

Answer:

r(t) = 15t+500

Step-by-step explanation:

Since the amount of money (r) is a function of the time (t) we will make it the y-value.  t is how much time and he gets $15 a minute so we multiply t by 15.  500 is how much he gets paid for doing it.  If he showed up and just left, he would still get 500.

8 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
4 years ago
If mAGF = mBGC = mDGC = mEGF = 70°, what is mAGB?<br> A.40° <br> B.70° <br> C.110° <br> D.35°
Tresset [83]
B it's going to work
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3 years ago
Ingrid is making a quilt using squares that measure 5in on each side. What is the length of a diagonal of one of the quilt squar
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5 inches because all lines/sides on a square are equivalent.
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3 years ago
Complete the equation of the graphed linear function in point-slope form.
BlackZzzverrR [31]
They are using the point (2, 8) to write this equation.  You know that because of the "y-8" in the equation, and also because it's bolded! lol.  Anyways, what's missing is the slope and the x value from our point.  The slope is -2.  Find this by picking 2 points on the line and putting those into the slope equation.  Use the bolded point and the x-intercept: (2,8) and (6,0):m= \frac{0-8}{6-2}= \frac{-8}{4}=-2.  As stated earlier the x coordinate in the bolded point is 2.  So our equation is y-8=-2(x-2).  And there you Go!
4 0
4 years ago
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