Will give brainliest give the answer and steps

The approximate dimensions of an olympic size swimming pool are 164ft by 82ft by 6ft?what is the volume?

harkovskaia [24]

To find the volume multiply the length by the width by the depth.

Volume = 164 x 82 x 6 = 80,688 cubic feet.

7 0

3 years ago

Read 2 more answers

What do you think Ginsburg is saying about a judge's role in the Supreme Court?

VLD [36.1K]

$\huge\mathfrak\red{Answer}$

Ruth Bader Ginsburg began her career as a justice where she left off as an advocate, fighting for women's rights. In 1996, Ginsburg wrote the majority opinion in United States v. Virginia, holding that qualified women could not be denied admission to Virginia Military Institute.

✔❤

4 0

3 years ago

For the following data set, select the best method for summarizing the data.

Rasek [7]

D

Step-by-step explanation:

the mean is the average of the set of numbers, which makes it perfect for summarizing data.

6 0

3 years ago

Are ABC and CDA congruent? Justify your answer. brainly

Setler79 [48]

Yes
because they have the same volume

5 0

3 years ago

Read 2 more answers

Help differentiate this

Arte-miy333 [17]

Answer:

$\displaystyle y' = 20x^3 + 6x^2 + 70x + 9$

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Terms/Coefficients
Expand by FOIL
Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = (x^3 + 7x - 1)(5x + 2)$

Step 2: Differentiate

Product Rule: $\displaystyle y' = \frac{d}{dx}[(x^3 + 7x - 1)](5x + 2) + (x^3 + 7x - 1)\frac{d}{dx}[(5x + 2)]$
Basic Power Rule [Derivative Property - Addition/Subtraction]: $\displaystyle y' = (3x^{3 - 1}+ 7x^{1 - 1} - 0)(5x + 2) + (x^3 + 7x - 1)(5x^{1 - 1} + 0)$
Simplify: $\displaystyle y' = (3x^2+ 7)(5x + 2) + 5(x^3 + 7x - 1)$
Expand: $\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5(x^3 + 7x - 1)$
[Distributive Property] Distribute 5: $\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5x^3 + 35x - 5$
Combine like terms: $\displaystyle y' = 20x^3 + 6x^2 + 70x + 9$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

4 0

2 years ago