9514 1404 393
Answer:
342 mm²
Step-by-step explanation:
The triangle shown has a base of 9 mm and a height of 76 mm. Its area is ...
A = 1/2bh
A = (1/2)(9 mm)(76 mm) = 342 mm²
The triangle shown has an area of 342 mm².
_____
<em>Additional comment</em>
The other leg of the right triangle with one leg 76 mm and hypotenuse 100 mm will be about 65 mm. The base shown is 9 mm, so any triangle with the dimensions shown will be a fairly skinny obtuse triangle, not the acute triangle in the picture. (This makes us suspect an error: the 9 mm dimension maybe should be 90 mm.)
The unit rate is 0.75 per x
9a)
4x - 2 + 30 = 68
4x + 28 = 68
4x = 40
x = 10
9b)
y = 180 -68
y= 112
Answer:
height = 20 cm
Step-by-step explanation:
The volume (V) of a cylinder is calculated using the formula
V = πr²h ← r is the radius and h the height
given r = 12 and V = 2880π, then
π × 12²h = 2880π
144πh = 2880π ( divide both sides by 144π )
h = 
= 20
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
