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horrorfan [7]
3 years ago
8

If Bill was traveling v mi/h, how would you represent Daemon's speed in mi/h if he was traveling 45 mi/h faster?

Mathematics
1 answer:
VikaD [51]3 years ago
5 0

The sum of two variables having the same units is given by adding the magnitudes of the quantities and expressing the outcome in the units of the quantities

Daemon's speed is (v + 45) mi/h

The reason the above value for Daemon's speed is correct is as follows:

The known parameters are;

The speed with which Bill was travelling = v mi/h

The speed with which Daemon was travelling = 45 mi/h faster than Bill

Method:

By dimensional analysis, we note that the given quantities have the same units, and therefore, they represent the same quantity of speed

To find Daemon's speed, the amount by which his speed is more than that of Bill's speed is added to the given amount of Bill's speed as follows;

Solution:

Daemon's speed = v mi/h + 45 mi/h = (v + 45) mi/h

Learn more about variable addition here:

brainly.com/question/22965573

brainly.com/question/242905

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So, we have 2a=6 \iff a=3

So, we want to complete the square (x+3)^2 = x^2+6x+9

We can add and subtract 9 to write

x^2+6x = x^2+6x+(9-9) = (x^2+6x+9)-9 = (x+3)^2-9

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3 years ago
For a printing company, the cost of printing business cards is a linear function, C(x) = 0.05x + 20, where x is the number of ca
Svetllana [295]

Answer:

80

Step-by-step explanation:

You plug in 1200 for x.

C(1200)=0.05(1200) +20

Then solve. Multiply first then add.

60+20

80

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3 years ago
The left and right page numbers of an open book are two consecutive integers whose sum is 389.  Find these page numbers
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Step-by-step explanation:

Maybe the page numbers can be 143 and 246

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4.One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in B
AleksAgata [21]

Answer:

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

Step-by-step explanation:

1) Data given and notation  

n=200 represent the random sample taken

X=63 represent the lawyers had used some form of advertising for their business

\hat p=\frac{63}{200}=0.315 estimated proportion of lawyers had used some form of advertising for their business

p_o=0.25 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that more than 25% of all the lawyers in Boston advertise for their business:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.315 -0.25}{\sqrt{\frac{0.25(1-0.25)}{200}}}=2.123  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.123)=0.0169  

The p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of lawyers had used some form of advertising for their business is significantly higher than 0.25 or 25% .  

8 0
3 years ago
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