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Olin [163]
3 years ago
10

Newton's formula for gravity depended on which two factors?

Chemistry
2 answers:
kompoz [17]3 years ago
6 0

Answer:

Newton's law also states that the strength of gravity between any two objects depends on two factors: the masses of the objects and the distance between them.

Explanation:

Answer is A.

<h2>Plz mrk me brainliest.</h2>
BartSMP [9]3 years ago
3 0
A. The mass of each object and how far away they are from each other :) the answer is A
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What is the temperature of gas and volume of gas
Nutka1998 [239]

Explanation:

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5 0
4 years ago
Suppose that you have 115 mL of a buffer that is 0.460 M in both benzoic acid ( C 6 H 5 COOH ) and its conjugate base ( C 6 H 5
77julia77 [94]

<u>Answer:</u> The maximum volume of HCl that can be added before its buffering capacity is lost is 111.3 mL

<u>Explanation:</u>

We are given:

Concentration of buffer = 0.460 M

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})        .....(1)

We are given:

pK_a = negative logarithm of acid dissociation constant of benzoic acid = 4.2

[C_6H_5COOH]=0.460M

[C_6H_5COO^-]=0.460M

pH = ?

Putting values in equation 1, we get:

pH=4.2+\log(\frac{0.460}{0.460})\\\\pH=4.2

When the pH of the buffer changes by 1 unit, the buffering capacity is said to be lost.

pH change for loosing buffer capacity = [4.2 - 1] = 3.2

Calculating the ratio of conjugate base and its acid by using equation 1:

pK_a = 4.2

pH = 3.2

Putting values in equation 1, we get:

3.2=4.2+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})\\\\\frac{[C_6H_5COO^-]}{[C_6H_5COOH]}=0.1

  • To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}        ......(2)

For benzoic acid and its conjugate base:

Molarity of benzoic acid and its conjugate base = 0.460 M

Volume of solution = 115 mL

Putting values in equation 2, we get:

0.460=\frac{\text{Moles of benzoic acid and its conjugate base}\times 1000}{115mL}\\\\\text{Moles of benzoic acid and its conjugate base}=\frac{0.460\times 115}{1000}=0.053mol

The chemical reaction for aniline and HCl follows the equation:

C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-

Let the moles of acid added to carry out the change is 'x' moles

  • Calculating the moles of acid added:

\frac{[C_6H_5COO^-]-x}{[C_6H_5COOH]+x}=0.1\\\\\frac{0.053-x}{0.053+x}=0.1\\\\x=0.0434

Calculating the volume of acid added by using equation 2, we get:

Moles of acid added = 0.0434 moles

Molarity of solution = 0.390 M

Putting values in equation 2, we get:

0.390M=\frac{0.0434\times 1000}{\text{Volume of acid}}\\\\\text{Volume of acid}=\frac{0.0434\times 1000}{0.390}=111.3mL

Hence, the maximum volume of HCl that can be added before its buffering capacity is lost is 111.3 mL

7 0
3 years ago
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Then you multiply this no. with Avagadro no....
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Decide which element probably has a boiling point most and least similar to the boiling point of cesium.
natka813 [3]

Answer:

Take a look at the attachment below

Explanation:

Take a look at the periodic table. As you can see, Rubidium is the closest element to Cesium, and happens to have the closest boiling point to Cesium, with only a difference of about 30 degrees.

Respectively, you would think that fluorine should have the least similarity to Cesium with respect to it's boiling point, considering it is the farthest away from the element out of the 4 given. This is not an actual rule, there are no fixed trends of boiling points in the periodic table, there are some but overall the trends vary. However in this case fluorine does have the least similarity to Cesium with respect to it's boiling point, a difference of about 1,546.6 degrees.

<em>Hope that helps!</em>

5 0
3 years ago
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