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Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is,
Explanation :
The given balanced reaction is,
Given:
Moles of hexane = 0.121 mol
= -8326 kJ/mol
The negative sign indicate that the reaction exothermic or amount of heat released.
As, 1 mole of hexane released heat = 8326 kJ
So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈
Therefore, the heat released by the combustion of 1.121 mol of hexane is .
Answer: The pressure in torr is 461 torr
Explanation:
To calculate the relation of density and molar mass of a compound, we use the ideal gas equation:
PV=nRT
P = pressure
V = Volume
n = number of moles
R = gas constant = 0.0821 Latm/Kmol
T = temperature =
Number of moles (n) can be written as:
where, m = given mass
M = molar mass = 44 g/mol
where,
where d = density = 2.54 g/L
The relation becomes:
PM=dRT
(760torr=1atm)
Thus the pressure in torr is 461 torr