Answer:
The percentage of germanium in germatite is 6.0003%.
Explanation:
Mass of an ore of germanite = 1.00 grams
Mass of germanium chloride = 0.177 grams
Percentage of germanium in germanium chloride = 33.9%
Let the mass of germanium present in germanium chloride be x.
Percentage of an element in a compound:
x = 0.060003 grams
Percentage of germanium in an ore of germanite:
The percentage of germanium in germatite is 6.0003%.
Answer:
d) Oxygen molecules will spread through both jars because of the high molecular weight of oxygen.
Explanation:
C. The heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
<h3>What is Specific heat capacity?</h3>
Specific heat capacity is the quantity of heat needed to raise the temperature per unit mass.
<h3>
Heat released when the aluminum is cooled </h3>
The heat released when the aluminum is cooled from 70°C to 50°C is calculated as follows;
Q = mcΔθ
where;
- m is mass of the aluminum
- c is specific heat capacity
- Δθ is change in temperature
Q = (10)(0.9)(50 - 70)
Q = -180 J
Thus, the heat released when the aluminum is cooled from 70°C to 50°C is -180 J.
Learn more about heat capacity here: brainly.com/question/16559442
#SPJ1
Not quite sure what you mean by matter ? Yes air is matter and yes it does matter ! Air is various gasses that support life and other things ! We use air for so many things, it's very important c:
Answer:
- 0.99 °C ≅ - 1.0 °C.
Explanation:
- We can solve this problem using the relation:
<em>ΔTf = (Kf)(m),</em>
where, ΔTf is the depression in the freezing point.
Kf is the molal freezing point depression constant of water = -1.86 °C/m,
m is the molality of the solution (m = moles of solute / kg of solvent = (23.5 g / 180.156 g/mol)/(0.245 kg) = 0.53 m.
<em>∴ ΔTf = (Kf)(m)</em> = (-1.86 °C/m)(0.53 m) =<em> - 0.99 °C ≅ - 1.0 °C.</em>
