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3 years ago

At what value of x does the minimum or maximum occur for the function below?

Mathematics

1 answer:

Luden [163]3 years ago

4 0

Answer:

Minimum at x=4

Hey I saw your new question.... If you just point about the points A and B in the graph I will gladly help you.

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The slope of graph below is shown? A-5/4 , B-5/4 , C-3/4, D-3?

olga nikolaevna [1]

Where’s the graph I don’t see it

7 0

3 years ago

I need help again.Here is the question, Distance = Rate x Time What was my rate of speed if it took me 3.5 hours to travel 210 m

Nimfa-mama [501]

Answer:

Step-by-step explanation:

210÷3.5=60

3.5x60=210

Hope this helps!

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3 0

3 years ago

Which of the following expressions represents

KatRina [158]

Answer:

$3k (m + \frac{1}{3}n)$

Step-by-step explanation:

Sum of m and one - third of n is :

$= m + \frac{1}{3}n$

Product of 3k to the sum is :

$=3k \times (m + \frac{1}{3}n)$

5 0

3 years ago

ILL GIVE BRAINLY THING

Leno4ka [110]

9514 1404 393

Answer:

d. The data is continuous because it is connected, without gaps.

Step-by-step explanation:

If you can draw the graph without lifting your pencil, then the data is continuous. That is the case here. The best description is the last one:

The data is continuous because it is connected, without gaps.

3 0

3 years ago

Determine whether or not the vector field is conservative. If it is conservative, find a function f such that F = ∇f. (If the ve

djyliett [7]

We're looking for $f(x,y,z)$ such that $\nabla f(x,y,z)=\vec F(x,y,z)$ , which requires

$\dfrac{\partial f}{\partial x}=xyz^2$

$\dfrac{\partial f}{\partial y}=x^9yz^2$

$\dfrac{\partial f}{\partial z}=x^9y^2z$

Integrating both sides of the first PDE wrt $x$ gives

$f(x,y,z)=\dfrac12x^2yz^2+g(y,z)$

Differenting this wrt $y$ gives

$\dfrac{\partial f}{\partial y}=x^9yz^2=\dfrac12x^2z^2+\dfrac{\partial g}{\partial y}$

$\implies\dfrac{\partial g}{\partial y}=\dfrac12x^2z^2(2x^7y-1)$

but we're assuming $g(y,z)$ is a function that doesn't depend on $x$ , which is contradicted by this result, and so there is no such $f$ and $\vec F$ is not conservative.

8 0

4 years ago