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den301095 [7]
3 years ago
13

How many 3/5 inch snicker bar are in 3 inches of snickers bars.

Mathematics
1 answer:
dexar [7]3 years ago
6 0

Answer:

there is 5 inches

Step-by-step explanation:

3/5= 5

You might be interested in
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
What is the solution to 3.2x = 6.4?
jeyben [28]
A. X = 2 
what you do is divide each side by the coefficient of x (3.2) to get rid of it on the left, and simplify the right: 2.

6 0
3 years ago
Marina deposits $1,500 in a savings account at Bank of America. The bank will pay her 5% interest at the end of the year. How mu
AURORKA [14]

Answer:

75 of additional money

Step-by-step explanation:

5% of 1,500 is 75

and 1,500 plus 75 is 1575

5 0
3 years ago
I need help ASAP PLEASE
White raven [17]
A) y= x+1
b) y= -2/3x-5
c) y=-1/2x+12
d) y= 4x-3/2
According to my calculations all the answers should be correct.
7 0
3 years ago
A Fraction Number: The sum of the numerator and denominator is 40. if its value is 3/5 after simplifying, what is the fraction b
katrin2010 [14]
Here: Fraction = 3/5
Let, original fraction (before simplifying) = 3x/5x
Then, 3x + 5x = 40
8x = 40
x = 40/8
x = 5

So, 3x = 3(5) = 15 & 5(5) = 25

In short, Your Answer would be 15/25

Hope this helps!
5 0
3 years ago
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