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GuDViN [60]
2 years ago
12

If you have 19 cups full of water and 45 gallons of water. what does the gallon equals to how many cups of water?​

Mathematics
1 answer:
BabaBlast [244]2 years ago
5 0

Answer:

45 divide by 19 =2 r 7 thanks

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Help!?!? Find the volume of the composite figure ​
34kurt

Answer:

288

Step-by-step explanation:

answer is in photo above

6 0
3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
Solve w^3 - 9w = 0 by factoring
madam [21]

Answer:

w = 0 , -3 , 3

Step-by-step explanation:

w³ - 9w = 0

w(w² - 9) = 0

w(w² - 3²) = 0

w(w+3)(w-3) = 0            {a² - b² = (a + b)(a - b) }

w = 0   ;  w + 3 = 0                ; w - 3 = 0

                     w = -3              ;        w = 3

w = 0 , -3 , 3

5 0
3 years ago
In the figure, x = , y = , and z = .
algol13
There’s no image attached, ask the question again
8 0
2 years ago
What is a ratio of 625 : 1296 simplified?
Georgia [21]

Answer:

625: 1296

Step-by-step explanation:

625: 1296 cannot be further simplified because they share no common factor.  The decimal form around 0.5822531

7 0
2 years ago
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