What is the point-slope form of a line that has a slope of 3 and passes through the point (-1, 4)?
2 answers:
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Answer:
x² + y² = 34
Formula:
- (x - h)² + (y - k)² = r² where (h, k) is the center
<u>Here find the radius using distance formula</u>: → origin : (0, 0)
- √(x2-x1)²+(y2-y1)²
- √(3-0)²+(5-0)²
- √9+25
- √34
<u>Thus the equation of circle</u>:
- (x - 0)² + (y - 0)² = (√34)²
- (x - 0)² + (y - 0)² = 34
- x² + y² = 34
Answer:
(i) ∠ABH = 14.5°
(ii) The length of AH = 4.6 m
Step-by-step explanation:
To solve the problem, we will follow the steps below;
(i)Finding ∠ABH
first lets find <HBC
<BHC + <HBC + <BCH = 180° (Sum of interior angle in a polygon)
46° + <HBC + 90 = 180°
<HBC+ 136° = 180°
subtract 136 from both-side of the equation
<HBC+ 136° - 136° = 180° -136°
<HBC = 44°
lets find <ABC
To do that, we need to first find <BAC
Using the sine rule
=
A = ?
a=6.9
C=90
c=13.2
=
sin A = 6.9 sin 90 /13.2
sinA = 0.522727
A = sin⁻¹ ( 0.522727)
A ≈ 31.5 °
<BAC = 31.5°
<BAC + <ABC + <BCA = 180° (sum of interior angle of a triangle)
31.5° +<ABC + 90° = 180°
<ABC + 121.5° = 180°
subtract 121.5° from both-side of the equation
<ABC + 121.5° - 121.5° = 180° - 121.5°
<ABC = 58.5°
<ABH = <ABC - <HBC
=58.5° - 44°
=14.5°
∠ABH = 14.5°
(ii) Finding the length of AH
To find length AH, we need to first find ∠AHB
<AHB + <BHC = 180° ( angle on a straight line)
<AHB + 46° = 180°
subtract 46° from both-side of the equation
<AHB + 46°- 46° = 180° - 46°
<AHB = 134°
Using sine rule,
=
AH = 13.2 sin 14.5 / sin 134
AH≈4.6 m
length AH = 4.6 m