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3 years ago

The quantities x and y are proportional.

Mathematics

2 answers:

mamaluj [8]3 years ago

6 0

Answer:

r = 7

Step-by-step explanation:

14 divided by 2 is 7

42 divided by 6 is 7

77 divided by 11 is 7

So the constant of proportionality is 7

r = 7

Anna [14]3 years ago

5 0

Answer:

Step-by-step explanation:

$y=rx\\77=r(11)\\7=r\\r=7$

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Which of these graphs represents the inequality x > 5?

nadezda [96]

Answer:

A is correct.

x>5 means all numbers greater than BUT not equal to 5.

The open circle means "not equal".

So, A is correct.

Hope this helps!

7 0

3 years ago

Read 2 more answers

The United States has trained some of the world's best computer programmers and technology experts. Despite all of this training

Finger [1]

Step-by-step explanation:

1. Many state students are looking for employment opportunities through outsourced jobs in other countries, since their possibilities have been reduced within their own country.

2.One of the independent variables is outsourced work.

a. a type of moderate independent variable.

3. The analysis of the high demand for outsourcing.

a. Control dependent variable.

4.It is an experimental design.

Because you want to see if the outsourced market really has any effect on the US economy.

6. Possible dependent variables such as the effect on the US market or the creation of new markets, I do not consider to be reliable variables to measure the cause or independent variable.

7.It is ecologically valid in the sense that it allows visualizing a positive impact on a way of working that allows reducing costs in all senses, both monetary and transportation, contributing to the care of nature.

8.I do not consider that cause and effect can be claimed.

a.While the one that exitates this type of outsourced work from many parts of the world, this does not guarantee that it is the only source of income for a person, since these outsourced jobs often represent additional income.

9. Focal groups.

7 0

3 years ago

Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o

GREYUIT [131]

Answer:

And then we can conclude that the middle 75% values of her lap times are from a=126.835 to b=132.585

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Solution to the problem

Let X the random variable that represent the times of a population, and for this case we know the distribution for X is given by:

$X \sim N(129.71,2.5)$

Where $\mu=129.71$ and $\sigma=2.5$

Since we want the middle 75% values then on tha tails we need 1-0.75 =0.25 or 25% of the data and since the distribution is symmetric we need 12.5 % of the values on each tail.

For this part we want to find a value a and b, such that we satisfy this condition:

$P(X>b)=0.125$ (a)

$P(X$ (b)

We can use the z score formula in order to find the value a and b given by:

$z=\frac{x-\mu}{\sigma}$

As we can see on the figure attached the z value that satisfy the condition (b) with 0.125 of the area on the left and 0.875 of the area on the right it's z=-1.15. On this case P(Z<-1.15)=0.125 and P(z>-1.15)=0.875

If we use condition (b) from previous we have this:

$P(X$

$P(z$

But we know which value of z satisfy the previous equation so then we can do this:

$z=-1.15$

And if we solve for a we got

$a=129.71 -1.15*2.5=126.835$

So the value of height that separates the bottom 12.5% of data from the top 87.5% is 126.835.

As we can see on the figure attached the z value that satisfy the condition (b) with 0.875 of the area on the left and 0.125 of the area on the right it's z=1.15. On this case P(Z<1.15)=0.875 and P(Z>1.15)=0.125

If we use condition (b) from previous we have this:

$P(X>b)=P(\frac{X-\mu}{\sigma}>\frac{b-\mu}{\sigma})=0.125$