All categories

3 years ago

Hey I need some help ASAP ill give 20 points

Mathematics

2 answers:

Alisiya [41]3 years ago

8 0

Answer:

241

Step-by-step explanation:

solve using pemdas

2^(8)-10-15/3

256-10-15/3

256-10-5

246-5

=241

Anna35 [415]3 years ago

6 0

Answer:

Step-by-step explanation:

2^8 - 10 - 15 ÷ 3 = ?

2^8 = 256

256 - 10 = 246

246 - 15 = 231

231 ÷ 3 = 77

<u><em>Any questions please ask them below.</em></u>

You might be interested in

17n + 8 =76 whats n ?

liubo4ka [24]

Answer:

Step-by-step explanation:

Step 1: Subtract 8 from both sides.

17n+8−8=76−8

17n=68

Step 2: Divide both sides by 17.

17n/17

68/17

Answer:4

7 0

4 years ago

Read 2 more answers

Pls help me. tyyyyyyyyyyyyyy<br>HAHA sorry for the volume thing in the way

rjkz [21]

<h2>Answer:</h2>

Triangle D

<h3>Hope this helps</h3>

5 0

3 years ago

Ben went to the farmer’s market with $14.00, bought 2 pounds of cherries and still had enough money left to buy 3 pounds of appl

Serggg [28]

Answer:

the price of 2 pounds of cherries is $14.00.

7 0

3 years ago

If there are 20 values in a data set in order from smallest to largest, what is

Natasha_Volkova [10]

Answer:

C The mean of the 10th and 11th values

Step-by-step explanation:

Strike the lowest and largest number until you get 1 or 2:

1, 2, 3,4 5,6 ,7 8, 9, 10, 11, 12, 13 ,14, 15, 16, 17, 18, 19, 20

2, 3,4 5,6 ,7 8, 9, 10, 11, 12, 13 ,14, 15, 16, 17, 18, 19

3,4 5,6 ,7 8, 9, 10, 11, 12, 13 ,14, 15, 16, 17, 18

4 5,6 ,7 8, 9, 10, 11, 12, 13 ,14, 15, 16, 17

5,6 ,7 8, 9, 10, 11, 12, 13 ,14, 15, 16,

,6 ,7 8, 9, 10, 11, 12, 13 ,14, 15

,7 8, 9, 10, 11, 12, 13 ,14,

8, 9, 10, 11, 12, 13

9, 10, 11, 12

10, 11,

Finding the Mean:

10+11

21/2

Mean:

10.5

8 0

3 years ago

Determine if the lim f(x) exists using the graph below.. If it does, find its value. If it does not,x 1explain why

Leno4ka [110]

The limit of a function f at a point a exists if:

$\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)$ $\begin{gathered} \text{ From the given image, the value of the left limit of f at x=1 } \\ \lim_{x\to a^-}f(x)\lt1 \end{gathered}$

Also,

$\begin{gathered} \text{ From the given image, the value of the right limit of f at x=1 } \\ \lim_{x\to a^+}f(x)\gt1 \end{gathered}$

Therefore,

$\lim_{x\to1^-}f(x)\lim_{x\to1^+}f(x)$

Hence, the limit does not exist

8 0

1 year ago