Answer:
d) All of the above
Step-by-step explanation:
A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).
In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.
In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.
This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.
The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.
Let's say we are comparing the means of k population. The degree of freedom would be = k - 1
The correct option here is (d).
All of the above
Answer:
4 weeks
Step-by-step explanation:
2 1/4 = 9/4 = 2.25
if it grows 2.25 inches in one week then in two weeks it would have grown 4.5 inches
keep adding the 2.25 inches to 14 until u get 23
:) hope this was heplful
The x is the independent variable of the number and the y is the dependent so find the one thats independent
Given:
Total number of questions = 6
Choice for each question (in MCQ) = 4
Assuming that no questions are left unanswered.
To find:
The total number ways to answer the quiz, assuming that no questions are left unanswered.
Solution:
Here, Number of ways to answer each question = 4
To find the total number ways to answer 6 MCQ, we have to have to multiply number of ways to answer each question 6 times.
Total number of ways to answer six-question quiz with 4-choice multiple choice questions is

Therefore, the required number of ways is 4096.
Answer:
Answer for the question :
A resercher is wondering whehter the drinking habits of adults in a certain region of the country are in the same proportion as the general population of adults. Suppose a recent study stated that the proportion of adults who reported drinking once a week or less in the last month was 0.26. The researcher's null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha; P> 0.26. The researcher collected datat from a random sample of 75 adults in the region of interest.
1- Verify that the normality assumption is satisfied. Describe each separately.
2- To cotinue the study into the drinking habits of adults, the researcher decides to collect datat from adults working in "blue collar" jobs to see whether their drinking habits are in the same proportion as the general public. The null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha: P>0.26. The researcher computer the test statistic to be 1.59. Draw a graph of z distribution, label the test statistic and shade the p-value associated with this test statistic."
is given in the attachment.
Step-by-step explanation: