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Naya [18.7K]
3 years ago
11

Someone please help out! Really need to pass :(

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
6 0

Answer:

ok ill help

Step-by-step explanation:

lilavasa [31]3 years ago
4 0

Answer:748yd spuared

Step-by-step explanation: use the area of a rhombus formula hope you pass hope this helps god bless

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Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
Which of the following values are in the range of the function graphed below?
Dafna1 [17]

Answer:

A. 1

Step-by-step explanation:

I see only one red function line in the graph. this line represents the simple function y = 1, for x in the interval [-2,1].

the domain of a function defines the possible values for x, and the range of a function defined the possible values for y.

this function has only one possible value for y : 1

so, only A applies.

5 0
3 years ago
3x^4 +x^3+4x-33<br> x^2+4
icang [17]

Answer:

3x^2 + x -12 + 15/(x^2+4)

Step-by-step explanation:

8 0
3 years ago
Can someone help me with both these problems?? Thx!
Vanyuwa [196]
#9 is yes because 12 is double 6. 6+6=12 I don't know #10. Sorry!
3 0
3 years ago
Solve by elimination<br> 5x+4y = 12<br> 3x - 3y = 18<br><br> Please help solve and provide steps.
SOVA2 [1]
First you solve for y.
5x+ y= 12 so Y= 12-5x
And plug it into the next equation
3x- 3(12-5x) = 18
Distribute
3x-36+15x=18
Add 36 to both sides
3x+ 15x= 54
18x= 54 ... divide
x= 3
And you can plug in x to solve for Y
5(3) + y = 12
15+ y = 12 ...subtract 15 from both sides
y= -3
4 0
3 years ago
Read 2 more answers
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