The area of a triangle is given by
... A = (1/2)bh
where b is the length of the base and h is the height perpendicular to the base. For your right triangle, the area is
... A = (1/2)(4 m)(7 m) = 14 m²
The area of a circular sector is given by
... A = (1/2)r²·sin(α)
where r is the radius and α is the angle in radians. For your sector, the area is
... A = (1/2)(4 m)²sin(60°) = 4√3 m²
Then the area of the base of your cylinder is the sum of these, ...
... B = (14 + 4√3) m²
The volume of a cylinder is the product of its base area and height.
... V = Bh
For your cylinder, that volume is
... V = ((14 +4√3) m²)·(8 m)
... V = (112 +32√3) m³ ≈ 167.43 m³
Answer:
2/3
Step-by-step explanation:
Find two points
(0,-2) and (3,0)
Using the slope formula
m = (y2-y1)/(x2-x1)
= (0- -2)/(3-0)
= (0+2)/(3-0)
= 2/3
Answer:
given
hope it helps!
Step-by-step explanation:
(10x^3y^2/5x^-3y^44)
= (10/5)(x^3/x^-3)(y^2/y^44)
= (2)(x^6)(y^-42)
= 2x^6y^-42
(2x^6y^-42)^3
= 8x^6*3y^-42*3
= 8x^18y^-126
Answer:
1-B The arrow is moving to the left which means that each equation should be negative which'll result in a negative.
2-A
Line B has slope m = (-3/2-0)/(4-0) = -3/8. The given point is the y-intercept (b = 7), so your equation is
y = mx +b . . . . . . . don't confuse the intercept variable (b) with the name of the line (here I called it B)
y = (-3/8)x +7