$(\stackrel{x_1}{-4}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{(-4)}}}\implies \cfrac{-6}{2+4}\implies \cfrac{-6}{6}\implies -1$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-1}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-3=-1(x+4)\implies y-3=-x-4\implies y=-x-1$

7 0

2 years ago

Jackson hikes 220.2 meters up a mountain. If he is 60% of the way up, how tall is the mountain?

PolarNik [594]

Answer would be C 367 meterss

8 0

3 years ago

At the moment, a physical therapist has 9 9/12 rolls of medical tape on hand. He anticipates using up 6 6/12 rolls while working

mart [117]

Answer:

subtract 6.5 by 9.75

Step-by-step explanation:

9/12 =.75

6/12=.5

9.75-6.5=3.25

hope this helps

°_°

3 0

3 years ago

Sin^2A-cos^2B=sin2^B-cos^2A

Rashid [163]

Answer:

see explanation

Step-by-step explanation:

Using the trig identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x

cos²x = 1 - sin²x

Consider the left side

sin²A - cos²B

= (1 - cos²A) - (1 - sin²B) ← distribute parenthesis

= 1 - cos²A - 1 + sin²B

= sin²B - cos²A

= right side , thus verified

7 0

3 years ago