All categories

3 years ago

When x is decreased by 129 and then that number is multiplied by 129, the result is 129. What is the value of x?

Mathematics

1 answer:

myrzilka [38]3 years ago

4 0

Answer:

Step-by-step explanation:

twice the difference of a number and 3 is added to 4

You might be interested in

PLS HELP Find the m∠RLU.<br> A. 10º<br> B. 6º<br> C. 25º<br> D. 50º

alexdok [17]

Rlu is 50 as rlu and alu are equal

7 0

3 years ago

On Melissa's 6th birthday, she gets a $2000 CD that earns 7% interest compounded quarterly. If the CD matures on her 13th birthd

Alexandra [31]

Answer:

$A\simeq3250.83$

Step-by-step explanation:

The amount formula in compound interest is:

$A=P(1+\frac{r}{n} )^{nt}$

where:

P = principal amount

r = annual interest

n = number of compounding periods

t = number of years

We already know that:

P = $2000

$r = 7\% = \frac{7\%}{100\%}=0.07$

t = 7 (number of years from 6th to 13th bday)

n = 4 (quarterly in a year)

Then,

$A=2000(1+\frac{0.07}{4} )^{(4)(7)}\\\\A=2000(1+\frac{0.07}{4} )^{28}\\\\A=3250.825792\\\\A\simeq3250.83$

8 0

2 years ago

Answer pleaseee!!!!!!!

stiks02 [169]

3 x 1/8 bottom left. The third one

4 0

3 years ago

If PQ bisects Angle RPS and measure of angle RPS = 120°, find p and measure of angle RPQ.

Ghella [55]

Answer:

p = 6; RPQ = 60 degrees

Step-by-step explanation:

Because RPS is 120 degrees and it is bisected by PQ (cut into 2 equal parts), we can determine that both sides are 60 degrees. Set the expression 5p+30 equal to 60 to find the value of p.

5p + 30 = 60

5p = 30

p = 6

So now you have determined that p = 6, and the measure of RPQ is 60 degrees.

Hope this helped!

8 0

3 years ago

Read 2 more answers

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

3 0

3 years ago