T probability of rolling doubles after 45 tosses is 0.156
<h3>How to determine the regression equation?</h3>
To do this, we enter the data values in a graphing calculator.
From graphing calculator, we have the following summary:
- Sum of X = 550
- Sum of Y = 87
- Mean X = 55
- Mean Y = 8.7
- Sum of squares (SSX) = 8250
- Sum of products (SP) = 1375
The regression equation is
y = bx + a
Where
b = SP/SSX = 1375/8250 = 0.16667
a = MY - bMX = 8.7 - (0.17*55) = -0.46667
So, we have:
y = 0.16667x - 0.46667
Approximate
y = 0.167x - 0.467
When the number of tosses is 45, we have:
y = 0.167 * 45 - 0.467
Evaluate
y = 7.048
Approximate
y = 7
45 tosses gives 7 doubles.
So, the probability is:
P = 7/45
Evaluate
P = 0.156
Hence, the probability of rolling doubles after 45 tosses is 0.156
Read more about regression equation at:
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Answer:
(x-1)^2+(y+19/8)^2=2665/64
Step-by-step explanation:
The general equation of a circle is
(x - h)^2 + (y - k)^2 = r^2
Substituting the values of the 3 given points:
(-5 - h)^2 + (0 - k)^2 = r^2
(0 - h)^2 + (4 - k)^2 = r^2
(2 - h)^2 + (4 -k)^2 = r^2
Subtracting the second equation from the first:
(-5-h)^2 - h^2 + k^2 - (4 - k)^2 = 0
25 + 10h + h^2 - h^2 + k^2 - 16 + 8k - k^2 = 0
10h + 8k = -9 ------------ (A).
Subtract the third equation for the second:
h^2 - (2 - h)^2 + 0 = 0
h^2 - 4 + 4h - h^2 = 0
4h = 4
h = 1.
Substituting for h in equation A:
10 + 8k = -9
8k = -19
k = -19/8
So r^2 = (-5-1)^2 + (0 + 19/8)^2 =
36 + 361/ 64
= 2665/64
Answer:
y= 1/3x - 1
Step-by-step explanation:
1/3 is slope so m and -1 is the y-intercept
Answer:
Square root of 34
Step-by-step explanation:
a^2 +b^2 =c^2
3^2 + 5^2 = 34
