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jeka57 [31]
2 years ago
12

Please I need help! I will give brainliest to whoever answers also! Thank you!!

Mathematics
1 answer:
Mazyrski [523]2 years ago
5 0

Answer:

No, If there equivalent they don't have to be equal. And if they are equal then don't have to be equivalent

Step-by-step explanation:

Hopes this helps.

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Answer:

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nirvana33 [79]

Answer:

-11

Step-by-step explanation:

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6 0
3 years ago
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Find the value of x³+ y³ + z³ – 3xyz if x² + y² + z² = 83 and x + y + z = 15​
raketka [301]

identity used is

x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).

then use

(x+y+z)² = x²+y²+z²+2(xy+yz+xz)

225= 83 + 2(xy+yz+xz)

xy+yz+xz = (225-83)/2

xy+yz+xz= 142/2

xy+yz+xz= 71

ok

now use identity

x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).

now

x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).

= 15[83 - (71)]

= 15×12

=180

4 0
3 years ago
What is the missing statement for step 4?
Pepsi [2]
What is step 4??? What is the statement?
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3 years ago
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