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kramer
3 years ago
10

How can you determine if a relationship is a direct variation from an equation? A table? A graph?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0
You can plug in the table or graph into the equation or the other way around to check your answer
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the owner of business decides to replaces the carpet in the office with carpet tiles. each tile is a square with sides measuring
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100 cm is the correct answer i am pretty sure
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3 years ago
Write the equation of a line that is perpendicular to y=0.3x+6 and that passes through the point (3,-8)
Harman [31]

<u>First, find the perpendicular slope</u>

y = 0.3x + 6   ⇒ m = 0.3  = \frac{3}{10}

perpendicular slope =  -\frac{10}{3}

<u>Next, input</u> the point (x₁, y₁) and slope (m) into the Point-Slope formula

  y - y₁ = m(x - x₁)

y - (-8) = -\frac{10}{3}(x - 3)

 y + 8 = -\frac{10}{3}x + 10

      y = -\frac{10}{3} + 2


5 0
3 years ago
X^(4)+1x^(3)-10x^(2)+dx-10 if x-2 is a factor what is the value of D
bulgar [2K]

Answer:

is there a picture to that ?

3 0
3 years ago
The measure of angle is 5. The equivalent measurement in degrees is... ​
balu736 [363]

Answer:

300 degrees

Step-by-step explanation:

pi should be 180 degrees so 5*180/3 = 5*60=300

6 0
1 year ago
Match the circle equations in general form with their corresponding equations in standard form. x2 + y2 − 4x + 12y − 20 = 0 (x −
Lemur [1.5K]
The equation form of a circle is (x - a)² + (y - b)² = r²

Equation 1:

x² - 4x + y² + 12y - 20 = 0 ⇒ use the completing the square method for x² - 4x and y² + 12y

x² - 4x = (x - 2)² - 4
y² + 12y = (y + 6)² - 36

Put them back together, we have
(x - 2)² - 4 + (y + 6)² - 36 - 20 = 0
(x - 2)² + (y + 6)² -4 - 36 - 20 = 0
(x - 2)² + (y + 6)² - 60 = 0
(x - 2)² + (y + 6)² = 60

Equation 2:

x² + y² + 6x - 8y - 10 = 0
(x² + 6x) + (y² - 8y) -10 = 0
(x + 3)² - 9 + (y - 4)² -16 - 10 = 0
(x + 3)² + (y - 4)² - 9 - 16 - 10 = 0
(x + 3)² + (y - 4)² - 35 = 0
(x + 3)² + (y - 4)² = 35

Equation 3:

3x² + 12x + 3y² +18y - 15 = 0
3 [x² + 4x + y² + 6y - 5] = 0
x² + 4x + y² + 6y - 5 = 0
(x² + 4x) + (y² + 6y) - 5 = 0
(x + 2)² - 4 + (y + 3)² - 9 - 5 = 0
(x + 2)² + (y + 3)² - 4 - 9 -5 = 0
(x + 2)² + (y + 3)² - 18 = 0
(x + 2)² + (y + 3)² = 18

Equation 4:

5x² + 5y² - 10x + 20y - 30 = 0
5 [x² + y² - 2x + 4y - 6] = 0
x² + y² - 2x + 4y - 6 = 0
(x² - 2x) + (y² + 4y) - 6 = 0
(x - 1)² - 2 + (y + 2)² - 4 - 6 =0
(x - 1)² + (y + 2)² - 2 - 4 - 6 = 0
(x - 1)² + (y + 2)² - 12 = 0
(x - 1)² + (y + 2)² = 12

Equation 5:

2x² + 2y² - 24x - 16y -8 = 0
2 [x² + y² - 12x - 8y - 4] = 0
x² + y² - 12x - 8y - 4 = 0
(x² - 12x) + (y² - 8y) - 4 = 0
(x - 6)² - 36 + (y - 4)² - 16 - 4 = 0
(x - 6)² + (y - 4)² -36 - 16 - 4 = 0
(x - 6)² + (y - 4)² - 56 = 0
(x - 6)² + (y - 4)² = 56

Equation 6:

x² + y² + 2x - 12y - 9 = 0
(x² + 2x) + (y² - 12y) - 9 = 0
(x + 1)² - 1 + (y - 6)² - 36 - 9 = 0
(x + 1)² + (y - 6)² - 1 - 36 - 9 = 0
(x + 1)² + (y - 6)² - 46 = 0
(x + 1)² + (y - 6)² = 46


3 0
3 years ago
Read 2 more answers
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