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3 years ago

Which answer choice best fits the given word;

1 answer:

8 0

Answer: Sometimes, two angles are a part of each other or are connected to each other. These angles are called angle pairs.

Let's look at two special types of angle pairs, supplementary angles or complementary angles.

Supplementary angles are two angles whose sum is equal to 180∘. In other words when you add the measure of one angle in the pair with the other angle in the pair, they equal 180 degrees.

These two angles are supplementary because together they form a straight line. You can also tell that they are supplementary because when you add their angle measures the sum is equal to 180 degrees.

120+60=180∘

Complementary angles are a pair of angles whose sum is 90∘. Here is an example of complementary angles.

If you add up the two angle measures, the sum is equal to 90 degrees. Therefore, the two angles are complementary.

You can find missing angle measures by using information about supplementary and complementary angles.

Let's look at an example.

Find the measure of x.

First, identify that these two angles are supplementary. They form a straight line. The total number of degrees in a straight line is 180. Therefore, you can write the following equation to solve.

130+xx=180=50∘

The missing angle is equal to 50∘.

Here the two angles are complementary. Therefore the sum of the two angles is equal to 90 degrees. Write an equation and solve for the missing angle measure.

75+xx=90=15∘

The missing angle measure is equal to 50∘.

Examples

Example 1

Earlier, you were given a problem about Paul and the house.

He has an angle pair that is formed by two 90 degree angles. What type of angle pair is formed when two 90 degree angles are combined?

First,add the two angles to calculate their sum.

90 + 90 = 180

Then, identify which angle pair adds up to 90 degrees.

Supplementary angles

The answer is that the pair are supplementary angles.

Example 2

Identify the angle pair as complementary or supplementary.

First, add the two angles to calculate their sum.

75 + 105 = 180

Then, identify which angle pair adds up to 180 degrees.

Supplementary angles

The answer is supplementary angles.

Write whether each pair is complementary or supplementary.

Example 3

Identify the angle pair as complementary or supplementary.

If the sum of the angles is equal to 180 degrees.

First, identify which angle pair adds up to 180 degrees.

Supplementary angles

The answer is supplementary angles.

Example 4

Identify the angle pair as complementary or supplementary.

If one angle is 60 degrees and the other angle is 120 degrees.

First, add the two angles together to find the sum.

60 + 120 = 180

Then, identify which angle pair adds up to 180 degrees.

Supplementary angles

The answer is supplementary angles.

Example 5

Identify the angle pair as complementary or supplementary.

First, add the two angles to calculate their sum.

30 + 60 = 90

Then, identify which angle pair adds up to 90 degrees.

Complementary angles

The answer is that the pair are complementary angles.

Step-by-step explanation:

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Alice and Bob each choose at random a number between zero and two. We assume a uniform probability law under which the probabili

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Before we start to answer this question, it would be nice to understand some basic definition and principles:

Random: This refers to an unpredictable pattern of arrangement. Without a specific aim or logical procedural pattern.

Uniform Probability distribution: This is a type of probability distribution in which the outcomes of distribution irrespective of the pattern or distance results in equally likely outcomes.

Uniform distribution is one of the widely used distributions although it's one of the simplest ones. The idea behind this distribution is that, unlike the other distributions, the likelihood of the any outcome in the distribution range is the same.

Now that we have a brief knowledge of the key terms within the question, hence, to start answering the question,

(a) Starting with 0 for Alice, Bob can choose any number starting from 1 / 3 . As Alice increases, Bob has to increase his starting point as well. Therefore, after Alice passes 1 / 3 , Bob can start choosing numbers from 0. This creates 2 triangles with sides 1 / 3 . The area of them gives us the probability.

Therefore, : P = 2 ( 1/3 1/3 1/3)

= 4/9

(b) We can find the probability of having both the numbers less than 1 / 3 . Then we subtract this probability from 1.

We have: P = 1 - 1/3 . 1/3

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(c) This is basically impossible as the area of a dot is negligible.

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3 years ago

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

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