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vlada-n [284]
3 years ago
10

you are swimming each a 25-yard lap pool 3 seconds faster than your personal best what integer represents your change in time of

your personall best after 200 yards
Mathematics
1 answer:
True [87]3 years ago
7 0
24 seconds faster than your best
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What are the x-intercepts of the graph of the quadratic function
Svetllana [295]
  • Zero Product Property: if a × b = 0, then either a or b = 0 or both a and b = 0.

(Make sure to set f(x) to zero)

So for this equation, I will be factoring by grouping. Firstly, what two terms have a product of -5x^2 and a sum of 4x? That would be 5x and -x. Replace 4x with 5x - x: 0=5x^2+5x-x-1

Next, factor 5x^2 + 5x and -x - 1 separately. Make sure that they have the same quantity on the inside: 0=5x(x+1)-1(x+1)

Now you can rewrite the equation as: 0=(5x-1)(x+1)

Now apply zero product property to the factors to solve for x:

5x-1=0\\5x=1\\x=\frac{1}{5}\\\\x+1=0\\x=-1

<u>The x-intercepts are (1/5 ,0) and (-1,0).</u>

5 0
3 years ago
Please help i know it a lot but please
blsea [12.9K]

Answer:

I have no clue

Step-by-step explanation:

I'm in middle school I don't know

6 0
2 years ago
PLEASE HELP! I WILL GIVE BRAINLIEST!<br> A<br> B<br> C<br> D
ra1l [238]

Answer:

C

Step-by-step explanation:

it goes in 0.1

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8 0
2 years ago
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Solve in degrees. 0 &lt; θ &lt; 360<br> 1. tan θ = 3.5134
Temka [501]

Answer:

Therefore,

\theta=74.11\°\ or\ \theta=254.11\°

Step-by-step explanation:

Given:

0° < θ < 360°

tan θ = 3.5134

To Find:

θ in degrees = ?

Solution:

0° < θ < 360° .............Given

Means ' θ ' is between 0° and 360°

\tan \theta=3.5134 .............Given

Therefore,

\theta=\tan^{-1} (3.5134)

Also,

\tan (180+\theta)=\tan \theta

So  ' θ '  will have Two values for tan θ =3.5134

\therefore \theta=74.11\°\ or\ \theta=180+74.11=254.11\°

Therefore,

\theta=74.11\°\ or\ \theta=254.11\°

5 0
3 years ago
ΔTOY has coordinates T (−3, 4), O (−4, 1), and Y (−2, 3). A translation maps point T to T' (−1, 1). Find the coordinates of O' a
Setler79 [48]
Given:
T (-3,4) ; O (-4,1) ; Y (-2,3)
T'(-1,1) ; 

T
-3 move forward 2 points to reach -1
4 move forward 3 points to reach 1

O
-4 move forward 2 points to reach -2
1 move forward 3 points to reach -2

Y
-2 move forward 2 points to reach 0
3 move forward 3 points to reach 0.

O'(-2,-2) ; Y'(0,0)   1st option.

3 0
3 years ago
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