These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer:
a.) Commutative Property of addition
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
A coefficient is a numerical factor that contains a variable.
In this case, 3 is a numerical factor and contains a variable (y).
Hence,
3 is the coefficient of the expression.
Answer:
the answer is d.
Step-by-step explanation:
as soon as you go to the theater, you HAVE to pay $5 in theater a, with two dollars for ONE snack bought, and it says two dollars PER one snack bought. therefore if x was 2, so if someone wanted to buy 2 snacks, then you would multiply by 2 to get the total cost, or y, for the snacks. answer d is the only one that has the correct numbers in the correct places for theater a and b.
hope this helps!
Answer:
Option B is correct
Step-by-step explanation:
We need to find g(h(f(x))
We first find h(f(x))
f(x) = x-3/x
Putting value of f(x) in place of x in h(x)
h(x) = 2x+1
h(f(x)) = 2(x-3/x) + 1
= 2(x-3/x) + 1
= 2x -6 /x +1
= 2x-6 +x/x
= 3x-6/x
Now, putting value of h(f(x)) in g(x)
g(x) = x+3
g(h(f(x)))= (3x-6/x) + 3
= 3x-6/x + 3
= 3x-6+3x/x
= 6x-6/x
So, Option B is correct.
