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Oksanka [162]
3 years ago
5

Classify: 2 7/9 A. real number B. whole number C. irrational number D. integer

Mathematics
2 answers:
GarryVolchara [31]3 years ago
8 0
Its not B or C

I thinks its A
SVEN [57.7K]3 years ago
8 0
<span>2 7/9 = 25/9 = 2.77778

answer is A. real number</span>
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Write the definition of Congruent Segments<br>as a Biconditional Statement.​
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Answer:

A bi conditional statement is a combination of a conditional statement and its converse written in the if and only if form. Two line segments are congruent if and only if they are of equal length

Step-by-step explanation:

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3 years ago
Which inequality correctly compares Two-fifths, Six-sevenths, Five-eighths, and 1?
Ronch [10]

Answer:

<u>2/5 < 5/8 < 6/7 < 1 </u>

   <u>OR</u>    

<u>1 > 6/7 > 5/8 > 2/5</u>

Step-by-step explanation:

It is required to compare Two-fifths, Six-sevenths, Five-eighths, and 1

Two-fifths = 2/5

Six-sevenths = 6/7

Five-eighths = 5/8

So, the given numbers are: 2/5, 6/7, 5/8, and 1

We need to make the numbers in order from the least to the greatest or from the greatest to the least

The easy method is convert the rational numbers to decimal numbers

So,

2/5 = 0.4

6/7 ≈ 0.857

5/8 = 0.625

1 = 1

So, the numbers form the least to the greatest are:

0.4 , 0.625 , 0.857 , 1

So,

2/5 , 5/8 , 6/7 , 1

The inequality correctly compares the numbers are:

<u>2/5 < 5/8 < 6/7 < 1</u>

Or can be written from the greatest to the least as:

<u>1 > 6/7 > 5/8 > 2/5 </u>

6 0
3 years ago
ASAP The tee for the fourth hole on a golf course is 300 yards from the tee. On that hole, Marsha hooked her ball to the left, a
andrey2020 [161]

Answer:

C. 97.5 yd

Step-by-step explanation:

The distance between Marsha, the ball and the tee for the fourth hole, forms a triangle.

Thus, the distance between Marsha's ball and the hole can be calculated using the Cosine formula below:

c² = a² + b² - 2abcos(C)

Where,

c = distance between Marsha's ball and the hole = ?

a = distance between the tee for the fourth hole and the tee = 300 yd

b = distance between tee and the hole = 255 yd

C = 18°

c² = 300² + 255² - 2(300)(255)cos(18)

c² = 90000 + 65025 - 153000 × 0.951

c² = 155025 - 145503

c² = 9522

c = √9522 ≈ 97.5

c = distance between Marsha’s ball and the hole = 97.5 yd (nearest tenth)

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3 years ago
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