Question

There is a bag with only milk and dark chocolates.

Answer 1

Answer:

12 milk chocolates.

Step-by-step explanation:

-We know that probabilities add upto 1:

$P(milk)+P(dark)=1\\\\P(milk)+\frac{7}{9}=1\\\\P(milk)=\frac{2}{9}$

Let X be the total number of chocolates. We know that probability is the successful events divided by the total number of events:

$P(dark)=\frac{dark \ events}{total \ events}\\\\\\\frac{7}{9}=\frac{42}{X}\\\\X=54$

#We subtract the number of dark chocolates from X to get the number of milk chocolates:

$N_m=X-N_d\\\\=54-42\\\\=12$

Hence, there must be 12 milk chocolates.