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joja [24]
3 years ago
6

Please help with this question.

Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:you have the correct answer

Step-by-step explanation:

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PLEASE HELP!!<br> 4 Digit Lock *<br> Enter 4 digit number code with no spaces
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6 0
2 years ago
Find the shortest distance, d, from the point (5, 0, −6) to the plane x + y + z = 6.
DENIUS [597]

Answer:

\frac{7}{\sqrt{3}}

Step-by-step explanation:

The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:

d = |\frac{(ma + nb + tc - r)}{\sqrt{m^2 + n^2 + t^2}} |                   --------------------(i)

From the question,

the point is (5, 0, -6)

the plane is x + y + z = 6

Therefore,

a = 5

b = 0

c = -6

m = 1

n = 1

t = 1

r = 6

Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

d = |\frac{((5) + (0) + (-6) - 6)}{\sqrt{1 + 1 + 1}} |

d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

Therefore, the shortest distance from the point to the plane is  d = \frac{7}{\sqrt{3}}

5 0
3 years ago
Please can someone answer this question quickly please<br><br> Thanks
inessss [21]

Answer:

C. 5/7

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Help Me for number 1 &amp; 2
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3 years ago
Which of the following statements must be true about parallelogram ABCD?
jolli1 [7]

Answer:

The answer is d

Step-by-step explanation:

Because all angles in parallelogram are the same

5 0
3 years ago
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