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frozen [14]
2 years ago
11

PLZ IM BEGGING YOU

Mathematics
1 answer:
antoniya [11.8K]2 years ago
5 0

Answer:

200

Step-by-step explanation:

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6. A high school graduate works fulltime. She needs to borrow $1,500 to
Rasek [7]

Answer:

I think you would have to multiply 1,500 by 12 and also by 18 to figure it out.

Step-by-step explanation:

" "

4 0
2 years ago
A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb
Maksim231197 [3]

Answer:

a) P(X = 1) = 0.38742

b) P(X = 3) = 0.05740

c) P(X = 9) = 0.00000

d) P(X \geq 5) = 0.00163

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

There are 10 containers, so n = 10.

A food-packaging apparatus underfills 10% of the containers, so p = 0.1.

a) This is P(X = 1)

P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742

b) This is P(X = 3)

P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740

c) This is P(X = 9)

P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000

d) This is P(X \geq 5).

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

P(X < 5) + P(X \geq 5) = 1

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868

P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742

P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937

P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740

P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742

So

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837

Finally

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163

3 0
3 years ago
What is the area in square units of the rectangle
Vsevolod [243]
\bf \textit{area of a rectangle}\\\\&#10;A=length\cdot width\qquad \qquad A=\cfrac{3}{7}\cdot \cfrac{2}{9}\implies A=\cfrac{6}{63}\implies A=\cfrac{2}{21}
8 0
3 years ago
Find the margin of error for a 90% confidence interval when the standard deviation is LaTeX: \sigma= 50????=50 and LaTeX: n = 25
Murrr4er [49]

Answer:

The margin of error  for a 90% confidence interval is 16.4

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 25

Standard deviation = 50

z_{critical}\text{ at}~\alpha_{0.10} = \pm 1.64

Margin of error =

z_{critical}\times \dfrac{\sigma}{\sqrt{n}}

Putting the values, we get,

1.64\times \dfrac{50}{\sqrt{25}} = 16.4

Thus, the margin of error  for a 90% confidence interval is 16.4

8 0
3 years ago
HELP IN THIS QUESTION
Shalnov [3]
The answer is 2/9 of a gallon.
Because 2/9 x 9 (people) is 2 (gallon)
7 0
3 years ago
Read 2 more answers
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