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3 years ago

What is-12÷3×(-8+(-4)2-6)+2

Mathematics

1 answer:

Gennadij [26K]3 years ago

6 0

)Answer:

Step-by-step explanation:

first of all solve bracket(-8+(-4)2-6)= -8-8-6= -22

add - 22 + 2 = 20

-12 div by 3 = - 4

at and multiply - 4 * 20 = -80

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Can a variable squared be combined with a variable

yanalaym [24]

Yes most likely a variable square can be combined with a variable I believe

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3 years ago

Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)

Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- $tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}$

- $tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}$

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ $\frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)}$ ⇒ (1)

∵ $tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}$ ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ $\frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}$

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ $\frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}$

- Simplify up and down

∴ $\frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }$

∴ $\frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}$

- Take tan(4x) as a common factor up

∴ $\frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}$

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0

3 years ago

What are the intercepts of the equation: 6x - y = 12

Arisa [49]

X=2 y= 12+6x, xeR

hope that helps

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3 years ago

The figure below is a diagram of a trapezoidal table that needs to be stained. Each can of stain will cover 50 square inches.

alekssr [168]

The perimeter is the sum of the outside dimensions.

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360 / 50 = 7.2 cans, round up to 8 cans are needed.

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3 years ago

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Nadusha1986 [10]

Answer:

Step-by-step explanation:

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4 years ago