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dimaraw [331]
3 years ago
15

PLEASE HELP!!! The stem-and-leaf plot shows the number of words in the classified ads in a newspaper one day.

Mathematics
2 answers:
Lilit [14]3 years ago
4 0

Answer:

D. 8

Step-by-step explanation:

We can see the numbers from 20 (inclusive) to 45 on the plot:

20, 20, 21, 24, 25, 33, 38, 38

In total 8 ads

Correct answer choice is: D. 8

OverLord2011 [107]3 years ago
4 0
D I’ve done this before
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Divide. Write the quotient in lowest terms. 1/4 ÷ 1 1/8<br><br> ​
natta225 [31]

Answer:2/11

Step-by-step explanation:

A fraction is in simplest form when the top and bottom cannot be any smaller

Firstly start by getting the common factors between 1 and 4 in 1/4 and 11 and 8 in 11/8. The common factor is 1 in 1/4 and 1 in 11/8. 1÷1/4÷1= 1/4. 11÷1/8÷1 = 11/8.

1/4÷ 11/8 =2/11.

3 0
3 years ago
Read 2 more answers
A pan of brownies is 7/10 full. Tyreese buys 2/5 of the brownies.
elixir [45]

Answer:

The answer to your question is below

Step-by-step explanation:

See the picture, please

In the first picture, we notice the initial amount of brownies (7/10), 7 brownies in a pan for 10 brownies.

After Tyreese bought 2/5   (7/10 - 2/5 = 3/10) there are 3 brownies left.

So in the picture, we notice only 3 brownies in a pan for 3 brownies.

6 0
3 years ago
The graph showsf(x)and its transformationg(x).
svlad2 [7]

Answer:

hope this helps you out good luck

6 0
3 years ago
Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5
masha68 [24]

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

3 0
2 years ago
Math question please help <br> If you get this right I will mark you as a brainliest
mixas84 [53]
What do you need help with
8 0
3 years ago
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