All categories

3 years ago

Allies plant has a height of 6meters. Radon’s plant grows 3/10 meters higher. How high does radon’s plant grow

Mathematics

1 answer:

kow [346]3 years ago

7 0

The height of Radon plant is 6.3 meters

Solution:

Given that, Allies plant has a height of 6 meters

Radon’s plant grows $\frac{3}{10}$ meters higher

To find: Height of Radon plant

From given information,

Height of Allies plant = 6 meters

Height of radon plant = $\frac{3}{10}$ + Height of Allies plant

Substituting the known value,

$\text{ Height of radon plant} = \frac{3}{10} + 6\\\\\text{ Height of radon plant} = \frac{3+60}{10}\\\\\text{ Height of radon plant} = \frac{63}{10}\\\\\text{ Height of radon plant} = 6.3$

Thus Radon plant grows to height of 6.3 meters

You might be interested in

The diameter of a circle Is 8 inches . What is the area ?

Elena L [17]

Answer:

radius=d/2 = 8/2 = 4inch.

Step-by-step explanation:

area = πr²

16π(inch)². or 352/7 (inch)².

hope this helps you.

8 0

2 years ago

Read 2 more answers

What are three equivalent ratios to 18/6

gayaneshka [121]

These could be be some of the answers to the problem. 6:3, 12:6, and 36:18

6 0

2 years ago

Read 2 more answers

NEED HELP, LIMITED TIME, HURRY

11111nata11111 [884]

Answer:

Step-by-step explanation:

here you go!

6 0

3 years ago

Read 2 more answers

−(−49) = −49 true or false?

vova2212 [387]

I hope this helps you

false

cause two negative numbers multiple must be positive

(-1).(-49)

+49

5 0

2 years ago

1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$