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2 years ago

Graph the line with slope -2.5 and y intercept -3

Mathematics

1 answer:

KengaRu [80]2 years ago

3 0

Answer: Posted in the picture

Step-by-step explanation: -2/5 is to the left since it is the x axis

and -3 is down since it is the y axis, so the answer is the black dot, on the left of the -3.

Hope this helps

And I hope I am right

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Let f(x) be defined for any positive integer x greater than 2 as the sum of all prime numbers less than x. For example, f(4)=2+3

blsea [12.9K]

Answer:

f(86)-f(82)

Step-by-step explanation:

well f of 82 = 2 plus _ plus _ plus _ and f of 86 is 2+_+_+_ subtract them

(A) 3 (B) 4 (C) 47 (D) 59 (E) 83

these are some possible answers so the answer is b, 4

btw, 86-82 = 4 duh

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2 years ago

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What is Y/-3 = 1/6,

telo118 [61]

Answer: y=1/2 of the whole

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2 years ago

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Simplify the following expression:<br> -8 (5b + 2) -7 ( b-5)

RUDIKE [14]

Answer:

-8(5b+2)-7(b-5)

first, use distributive property to get:

-40b-16-7b+35

then, use combine like terms to simplify:

-47b+19

that's your answer!

:)))))))))

3 0

3 years ago

Read 2 more answers

Does anyone know how to do this?? Help please!!!!

Doss [256]

Answer:

When we have a rational function like:

$r(x) = \frac{x + 1}{x^2 + 3}$

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

$\frac{1}{4} = \frac{x + 1}{x^2 + 3}$

We can multiply both sides by (x^2 + 3)

$\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)$

$\frac{x^2 + 3}{4} = x + 1$

Now we can multiply both sides by 4:

$\frac{x^2 + 3}{4}*4 = (x + 1)*4$

$x^2 + 3 = 4*x + 4$

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

$x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}$

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

$x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}$

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0

2 years ago

The same Honey is sold in two different size jars. Large jar= 540g for £4.10 Small jar= 360g for £2.81. By considering the amoun

Ray Of Light [21]

Answer:

From our calculations the large jar is the best value for money because a penny buys more honey

Step-by-step explanation:

<h2>In this problem we are expected to determine which purchase of honey is the cheapest ? large jar or small jar ?.</h2><h2 />

We will determine which has the best value for money using the quantity a pound can purchase.

firstly for the large jar.

if £4.10 will purchase 540g of honey then,

£1.00 will purchase xg

cross multiplying to find x will have

$x=$ $\frac{1.00*540g}{4.10}$

$x= 131.7grams$

Hence for the large jar a penny would buy 131.7g of honey

secondly for the small jar

if £2.81 will purchase 360g of honey then,

£1.00 will purchase xg

cross multiplying to find x will have

$x=\frac{1.00*360g}{2.81}\\x= 128.1gram$

Hence for the small jar a penny would buy 128.1g of honey

4 0

3 years ago