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dezoksy [38]
2 years ago
10

Amira decides to estimate the volume of an apple by modeling it as a sphere. She measures its circumference as 43.4 cm. Find the

apples's volume in cubic centimeters. Round your answer to the nearest tenth if necessary.
Mathematics
1 answer:
madam [21]2 years ago
7 0

The formula for the circumference of a circle (or a sphere) is 2\pi r\\.
The formula the volume of a sphere is \frac{4}{3}\pi r^3.
Assuming 43.4 includes the pi, we can do the equation 43.4=2\pi r
Solving the equation, we get \frac{43.4}{2\pi } =r

Substituting r into the formua for the volume of a sphere, we get \frac{4}{3} *\pi *(\frac{43.4}{2\pi } )^3
Solving the cube (probably with a calculator), we get \frac{4}{3} *\pi *\frac{81746.504}{8\pi ^3}

It is a bit messy, but we can simplify further by cancelling out the pi's, which leaves us with \frac{4}{3} *\frac{81746.504}{8\pi ^2}.
With the butterfly method (or whatever you may call it), we can cancel out the 4 in the numerator and the 8 in the denominator, and multiply the 3 in the denominators.
Which gets us this: \frac{81746.504}{6\pi ^2}
Using a calculator, we get our final answer of (about) 1380.44cm^3


This was very messy, I apologize if I did make any mistakes.

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Mamont248 [21]
It is asking you to find the sum of k^2 - 1 from k=1 to k=4. Since that is only 4 numbers, calculating the sum by hand wouldn’t be that bad.

(1^2 - 1) + (2^2 - 1) + (3^2 - 1) + (4^2 - 1) = 26

The easier way to find the sum is to use a few simple formulas.

When we have a term that is just a constant c, the formula is c*n.

When we have a variable k, the formula is k*n*(n+1)/2.

When we have a squared variable, the formula is k*n*(n+1)*(2n+1)/6.

In this case, we have a squared variable k^2 and a constant of -1.

So plug in n=4 to the formulas:

4*5*9/6 - 1*4 = 26

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3 years ago
Sinθ/cosθtanθ=1<br>how is this identity true?​
Yakvenalex [24]

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2 years ago
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Cumin has the least price per ounce

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5 0
4 years ago
A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

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Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

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Substitute r = \sqrt{(a)^2 + (b)^2}

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cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

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<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

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