The digit 2 would be in the hundred thousands place because if you say it out loud its "three million, two hundred fifty four thousand, one hundred and seven"
So we can start with the full of possibilities and eliminate them one by one.
The full set is {0,1,2,3,4,5,6,7,8,9}.
Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:
{1,3,5,7,9}
We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.
{1,3,7,9}
We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:
{1,3,7,9} as our answer.
Answer:
Step-by-step explanation:
2z+4x+9y-y+3
2z+4x+8y+3
=2z+4x+8y+3
Answer:
54+4.4 is greater
Step-by-step explanation:
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