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tekilochka [14]
3 years ago
12

Please show me how to do this!!

Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0
(2x^4 + 3x^2)(x^2-1)
you multiply and you'll get:
2x^8-2x^4+3x^4-3x^2
then add the coefficients with x^4
= 2x^8+1x^4-3x^2

 the coefficient for x^4 is 1, so the answer is B
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−4(3m−3)+(−10+8m)=?
Valentin [98]
-4(3m-3)+(-10+8m)
12m+12-1+8m
12m+8m = 20m
+12 -1= +11
answer: 20m+11


*note negative times a negative equals positive and negative times positive is negative 
first: you multiply -4 by 3m which is -12m.
second: you multiply -4 by -3 which is +12
third: find the invisible which is 1. (located right here: +(1) (-10+8m)
fourth: multiply invisible 1 by -10 which is -10
fifth: multiply invisible one by +8m which is +8m 
sixth: combine like terms
seventh: answer
 
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Step-by-step explanation:

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Jim filled nis gas tank three times last week. Here are the amounts of gas he bought (in gallons).
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in a weakly connected graph. it is not possible to reach all other vertices from any one vertext (true) (false)
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Read 2 more answers
ZEFG and ZGFH are a linear pair, mZEFG = 3n+ 21, and mZGFH = 2n + 34. What are mZEFG and mZGFH?
marysya [2.9K]

Answer:

The answer is below

Step-by-step explanation:

∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?

Solution:

Two angles are said to form a linear pair if they share a base. Linear pair angles are adjacent angles formed along a line as a result of the intersection of two lines. Linear pairs are always supplementary (that is they add up to 180°).

m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:

m∠EFG + m∠GFH = 180°

3n + 21 + (2n + 34) = 180

3n + 2n + 21 + 34 = 180

5n + 55 = 180

5n = 125

n = 25

Therefore, m∠EFG = 3(25) + 21 = 96°, m∠GFH = 2(25) + 34 = 84°

7 0
3 years ago
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