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Natasha2012 [34]
3 years ago
10

Put the numbers and fractions in order: 5; 4/5; 1,04; 2,3(4); -8/4; -1/3

Mathematics
1 answer:
strojnjashka [21]3 years ago
3 0

Answer:

be sure the force is velocity and again vo ahead

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Plz ans asap i havd limited time ill give brainliest
Artemon [7]

Answer:

C. $128

Step-by-step explanation:

320 x 0.5 = 160

320 - 160 = 160

160 x 0.20 = 32

160 - 32 = 128

5 0
3 years ago
Read 2 more answers
Pls help me ill give brainliest <br><br> Do all 3 pls to get brainliest
olya-2409 [2.1K]

Answer:

16.) c. 2x²+7x-15

17.) c. y=\frac{4}{9}x+\frac{17}{9}

18.) D

Step-by-step explanation:

have a wonderful day! :D

6 0
3 years ago
The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

3 0
3 years ago
Compare 2/8 to 1/2 write to explain you step by step
Softa [21]

Answer:

2/8 is one-half as much as 1/2

Step-by-step explanation:

Change the denominators to the same number.

2/8 is already okay

1/2=4/8

now

2/8 would be one-half as much as 4/8

7 0
3 years ago
Among all pairs of numbers whose difference is 6, find a pair whose product is as small as possible. What is the minimum product
kkurt [141]
Ummm if its multiply then its 1 and 6. is its addition then its 1 and 5 or 6 and 0. if its divide it would be 6 and 1. is its subtraction then it would be 7 and 1 or 6 and 0

3 0
3 years ago
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