Answer:
Step-by-step explanation:
you do your math!!
Remember (a²-b²)=(a-b)(a+b)
solve for a single variable
solve for y in 2nd
add y to both sides
x²-7=y
sub (x²-7) for y in other equaiton
4x²+(x²-7)²-4(x²-7)-32=0
expand
4x²+x⁴-14x²+49-4x²+28-32=0
x⁴-14x²+45=0
factor
(x²-9)(x²-5)=0
(x-3)(x+3)(x-√5)(x+√5)=0
set each to zero
x-3=0
x=3
x+3=0
x=-3
x-√5=0
x=√5
x+√5=0
x=-√5
sub back to find y
(x²-7)=y
for x=3
9-7=2
(3,2)
for x=-3
9-7=2
(-3,2)
for √5
5-7=-2
(√5,-2)
for -√5
5-7=-2
(-√5,-2)
the intersection points are
(3,2)
(-3,2)
(√5,-2)
(-√5,-2)
Answer:
I got x<equal to -11 or x>equal to4
Step-by-step explanation:
x^2+15x+44=0
(x+4)(x+11)=0(Factor left side of equation)
x+4=0 or x+11=0(Set factors equal to 0)
x=−4 or x=−11
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<−11(Works in original inequality)
−11<x<−4(Doesn't work in original inequality)
x>−4(Works in original inequality)
Answer:
x<−11 or x>−4
All you have to do is subtract 45 from 6:10. Which is 5:65pm she started
