Answer:
dcfvghbjk
Step-by-step explanation:
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
see below
Step-by-step explanation:
We can use point slope form
y - y1 = m(x-x1)
where m is the slope and ( x1,y1) is a point on the line
y-12 = 3(x-12)
If we want it in slope intercept form
Distribute
y-12 = 3x-36
Add 12 to each side
y-12+12 = 3x-36+12
y = 3x-24
[(x**-2) y**2 .z)**2]**2 (x**-8)(y**8)(z**4)
----------------------- = -----------------------------
[x**2 . y**3]**2 (x**4) (y**6)
(y**8)(z**4) (y**2)*(z**4)
--------------------- = -------------
(x**12) (y**6) (x**12)
