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bixtya [17]
2 years ago
9

Under certain​ conditions, the average cost of driving a medium sedan in 2012 was ​$0.64 per mile. How much would it have cost t

o drive such a car 13000 miles in​ 2012?
Mathematics
1 answer:
Snowcat [4.5K]2 years ago
7 0

Answer:

$8320

Step-by-step explanation:

.64 x 13000

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3 years ago
2z - 6 = 2(2 + 2) - 10
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Answer:

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Step-by-step explanation:

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<u>/2 /2</u>

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Hope this helps! Have a great day ^^

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3 years ago
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3 years ago
How to solve for linear equation 2/x+y/4=3/2
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3 years ago
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Rationalize the numerator. <br><img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B144x%20%7D%20%7D%7B%20%5Csq
Simora [160]

rationalizing the numerator, or namely, "getting rid of that pesky radical at the top".


we simply multiply top and bottom by a value that will take out the radicand in the numerator.


\bf \cfrac{\sqrt[3]{144x}}{\sqrt[3]{y}}~~&#10;\begin{cases}&#10;144=2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 3\\&#10;\qquad 2^3\cdot 18&#10;\end{cases}\implies \cfrac{\sqrt[3]{2^3\cdot  18x}}{\sqrt[3]{y}}\implies \cfrac{2\sqrt[3]{  18x}}{\sqrt[3]{y}}&#10;\\\\\\&#10;\cfrac{2\sqrt[3]{  18x}}{\sqrt[3]{y}}\cdot \cfrac{\sqrt[3]{(18x)^2}}{\sqrt[3]{(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)(18x)^2}}{\sqrt[3]{(y)(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)^3}}{\sqrt[3]{18^2x^2y}}


\bf \cfrac{2(18x)}{\sqrt[3]{324x^2y}}~~&#10;\begin{cases}&#10;324=2\cdot 2\cdot 3\cdot 3\cdot 3\cdot 3\\&#10;\qquad 12\cdot 3^3&#10;\end{cases}\implies \cfrac{36x}{\sqrt[3]{12\cdot 3^3x^2y}}&#10;\\\\\\&#10;\cfrac{36x}{3\sqrt[3]{12x^2y}}\implies \cfrac{12x}{\sqrt[3]{12x^2y}}

3 0
3 years ago
Read 2 more answers
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