Answer: 2.25 x 10 -7 -7 is the exponent
Step-by-step explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10 If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Hi!
Let's set up the equation.
![4^{a} - 2^{b} + 40](https://tex.z-dn.net/?f=4%5E%7Ba%7D%20-%202%5E%7Bb%7D%20%2B%2040%20)
Put in the values...
![4^{2} - 2^{7} + 40](https://tex.z-dn.net/?f=4%5E%7B2%7D%20-%202%5E%7B7%7D%20%2B%2040%20)
Now solve using PEMDAS
Exponents
![16 - 128 + 40](https://tex.z-dn.net/?f=16%20-%20128%20%2B%2040%20)
Subtract
![-112 + 40](https://tex.z-dn.net/?f=-112%20%2B%2040%20)
Add
![-72](https://tex.z-dn.net/?f=-72)
The answer is
-72
Hope this helps! :)
Answer:
The percent increase in the perimeter is 337.5%
Step-by-step explanation:
The easiest way to approach this problem is by using consecutively the simple rule of three.
If the first triangle has sides of length two then, we can compute the second triangle's sides length as follows:
2 units------100%
X units------150%
this way
.
Now for the third triangle we repeat the same process
3 units------100%
X units------150%
getting that the length of the sides for the third triangle is
.
Now for the last triangle we repeat the same process
4.5 units------100%
X units------150%
getting that the length of the sides for the last triangle is
.
Now, we need to know the perimeter of the first and last triangle. This can be calculated as the sum of the length of the sides of the triangle.
For the first triangle
![P_{first}=2+2+2\\P_{first}=6](https://tex.z-dn.net/?f=P_%7Bfirst%7D%3D2%2B2%2B2%5C%5CP_%7Bfirst%7D%3D6)
and for the last triangle
.
To compute the percent increase in the perimeter from the first to the fourth triangle we will use one last simple rule of three (this time the percentage will be the variable)
6 units------100%
20.25 units------X%
so
.
Answer and Step-by-step explanation:
<em>Rearrange the equation so "y" is on the left and everything else on the right.</em>
<em>Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)</em>
<em>Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).</em>
<em>Solve systems of equations by graphing. A system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. The solution of such a system is the ordered pair that is a solution to both equations. To solve a system of linear equations graphically we graph both equations in the same coordinate system. </em>
Have a Awesome day!