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MArishka [77]
3 years ago
12

Do the ratios 16/8 and 6/3 form a proportion? Yes or no?

Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0

Answer:

Yes. Reduce 16/8 by dividing by 8. 16/8= 2, 8/8= 1. 16/8= 2. Reduce 6/3 by dividing by 3. 6/3= 2 , 3/3= 1. 6/3= 2.

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\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

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