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lisabon 2012 [21]
3 years ago
11

A

Mathematics
1 answer:
motikmotik3 years ago
3 0

Answer:

50

Step-by-step explanation:

180-(x+80) + 180-(2x+20) = 180 -70

180-x-80 + 180-2x-20 = 110

100-x + 160-2x = 110

260 - 3x = 110

-3x = -150

x = <u>50</u>

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Can someone please help I can’t understanddd.
dem82 [27]

Hello,

Dividing by 0 is not defined so let s take x different from 4 and -4 and then we can write:

As

f(x)=x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)\\ \\(f\times g)(x)=\dfrac{3(x-4)(x-3)}{(x-4)(x+4)}=\dfrac{3x-9}{x+4}

Thanks

6 0
3 years ago
Derivative of tan(2x+3) using first principle
kodGreya [7K]
f(x)=\tan(2x+3)

The derivative is given by the limit

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

You have

\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}

By this identity, you have

\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}

So in the limit you get

\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}
\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}

The first two limits are both 1, and the single term in the last limit approaches 0 as h\to0, so you're left with

f'(x)=\dfrac12\sec^2(2x+3)

which agrees with the result you get from applying the chain rule.
7 0
3 years ago
N-9 = 13<br> ------------------
Vera_Pavlovna [14]

Answer:

n-9=13

n=22

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Trevon and Ming are selling cheesecakes for a school fundraiser. Customers can buy French silk cheesecake and apple cheesecake.
qwelly [4]

The cost of one French silk cheesecake is $5 and one apple cheesecake is $14.

Step-by-step explanation:

Let,

Cost of one French silk cheesecake = x

Cost of one apple cheesecake = y

According to given statement;

8x+y=54     Eqn 1

3x+y=29     Eqn 2

Subtracting Eqn 2 from Eqn 1

(8x+y)-(3x+y)=54-29\\8x+y-3x-y=25\\5x=25

Dividing both sides by 5

\frac{5x}{5}=\frac{25}{5}\\x=5

Putting x=5 in Eqn 1

8(5)+y=54\\40+y=54\\y=54-40\\y=14

The cost of one French silk cheesecake is $5 and one apple cheesecake is $14.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/10250188
  • brainly.com/question/10480770

#LearnwithBrainly

3 0
3 years ago
Evaluate 2.625-(-6)
Lunna [17]
2,625 - (-6) = 

= 2, 625 + 6 

= 8, 625
8 0
3 years ago
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