Answer: 233 people per thousand
Step-by-step explanation:
Using extrapolation method,
if 150/k in 1950,
200/k in 1990,
275/k in 2020,
2003 lies in between 1990 and 2020. So, you extrapolate the values of 200/k and 275/k for the years respectively.
Therefore,
(2003 - 1990)/(2020 - 2003) = (x - 200)/(275 - x)
Where x is the number of retirees per thousand for 2003
Making x the subject of relation in the above equation.
Cross multiply the equation above;
(2003 - 1990)(275-x) = (2020 - 2003)(x - 200)
13(275 - x) = 17(x-200)
3575 - 13x = 17x - 3400
Collect the like terms
3575+3400 = 17x + 13x
30x = 6975
x = 6975/30
x = 232.5
x = 233 people per thousand to the nearest integer
Using the speed - distance relationship, the time left before the appointed time is 27 minutes.
<u>Recall</u><u> </u><u>:</u>
<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>
- Distance = 10 × (t + 3) = 10t + 30 - - - (1)
<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>
- Distance = 12 × (t - 2) = 12t - 24 - - - - (2)
<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>
10t + 30 = 12t - 24
<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>
10t - 12t = - 24 - 30
-2t = - 54
<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>
t = 54 / 2
t = 27
Hence, the time left before the appointed time is 27 minutes.
Learn more : brainly.com/question/25669152
