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uranmaximum [27]
3 years ago
9

WILL GIVE BRAINLIEST PLEASE I NEED HELP

Mathematics
1 answer:
densk [106]3 years ago
6 0

The numbers on the left are the x values because the arrows are pointing away from them. The numbers in the right are the y values. Match the y value with the x value that the arrows are pointing from.

-2,-5 , -2,7 , 1,0 , 5,4 , 7, 0

The answer is C.

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An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What pr
konstantin123 [22]

Answer:

2.28% of tests has scores over 90.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 5

What proportion of tests has scores over 90?

This proportion is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.

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guitarist a&b I often their service to throne but each guitarist charge different intentional feeds and hourly rates how can the throne check to see when they will charge the same amount of money named three ways to perform this task answer

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