Draw a flow chart to print gratest number among two .
2 answers:
You might be interested in
<h2>Answer:</h2>
<u />
========= Shape.java ===========
//import the Scanner class
import java.util.Scanner;
public class Shape{
//required fields
private String shape;
private double area;
private double perimeter;
//default constructor
public Shape(){
this.shape = "unknown";
this.area = 0.0;
this.perimeter = 0.0;
}
//constructor with one parameter
public Shape(String shape){
this.setShape(shape);
this.area = 0.0;
this.perimeter = 0.0;
}
//accessors and mutators
public void setShape(String shape){
this.shape = shape;
}
public String getShape(){
return this.shape;
}
public double getPerimeter(){
return this.perimeter;
}
public double getArea(){
return this.area;
}
public void setPerimeter(Scanner scr){
if(this.getShape().equals("circle")){
System.out.println("Enter the radius of the circle");
double radius = scr.nextDouble();
this.perimeter = 2 * 3.142 * radius;
}
else if(this.getShape().equals("rectangle")){
System.out.println("Enter the width");
double width = scr.nextDouble();
System.out.println("Enter the height");
double height = scr.nextDouble();
this.perimeter = 2 * (width + height);
}
else if(this.getShape().equals("square")){
System.out.println("Enter the height or width");
double height = scr.nextDouble();
this.perimeter = 4 * height;
}
else if(this.getShape().equals("unknown")){
System.out.println("You must define a shape first before calculating perimeter");
this.perimeter = 0.0;
}
else {
System.out.println("You must define a shape first before calculating perimeter");
this.perimeter = 0.0;
}
}
public void setArea(Scanner scr){
if(this.getShape().equals("circle")){
System.out.println("Enter the radius of the circle");
double radius = scr.nextDouble();
this.area = 3.142 * radius * radius;
}
else if(this.getShape().equals("rectangle")){
System.out.println("Enter the width");
double width = scr.nextDouble();
System.out.println("Enter the height");
double height = scr.nextDouble();
this.area = width * height;
}
else if(this.getShape().equals("square")){
System.out.println("Enter the height or width");
double height = scr.nextDouble();
this.area = height * height;
}
else if(this.getShape().equals("unknown")){
System.out.println("You must define a shape first before calculating area");
this.area = 0.0;
}
else {
System.out.println("You must define a shape first before calculating area");
this.area = 0.0;
}
}
//Own methods
//1. Method to show the properties of a shape
public void showProperties(){
System.out.println();
System.out.println("The properties of the shape are");
System.out.println("Shape : " + this.getShape());
System.out.println("Perimeter : " + this.getPerimeter());
System.out.println("Area : " + this.getArea());
}
//2. Method to find and show the difference between the area and perimeter of a shape
public void getDifference(){
double diff = this.getArea() - this.getPerimeter();
System.out.println();
System.out.println("The difference is " + diff);
}
}
========= ShapeTest.java ===========
import java.util.Scanner;
public class ShapeTest {
public static void main(String [] args){
Scanner scanner = new Scanner(System.in);
// create an unknown shape
Shape shape_unknown = new Shape();
//get the shape
System.out.println("The shape is " + shape_unknown.getShape());
//set the area
shape_unknown.setArea(scanner);
//get the area
System.out.println("The area is " + shape_unknown.getArea());
//set the perimeter
shape_unknown.setPerimeter(scanner);
//get the perimeter
System.out.println("The perimeter is " + shape_unknown.getPerimeter());
// create another shape - circle
Shape shape_circle = new Shape("circle");
//set the area
shape_circle.setArea(scanner);
//get the area
System.out.println("The area is " + shape_circle.getArea());
//set the perimeter
shape_circle.setPerimeter(scanner);
//get the area
System.out.println("The perimeter is " + shape_circle.getArea());
//get the properties
shape_circle.showProperties();
//get the difference between area and perimeter
shape_circle.getDifference();
}
}
<h2>Sample output:</h2>
The shape is unknown
You must define a shape first before calculating area
The area is 0.0
You must define a shape first before calculating perimeter
The perimeter is 0.0
Enter the radius of the circle
>> 12
The area is 452.448
Enter the radius of the circle
>> 12
The perimeter is 452.448
The properties of the shape are
Shape : circle
Perimeter : 75.408
Area : 452.448
The difference is 377.03999999999996
<h2>Explanation:</h2>
The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark">
java
</span>
Answer:
I am writing the program in C++ programming language.
#include<iostream> // to use input output functions
using namespace std; // to identify objects like cin cout
class ProblemSolution { //class name
private:
// private data members that only be accessed within ProblemSolution class
int real, imag;
// private variables for real and imaginary part of complex numbers
public:
// constructor ProblemSolution() to initialize values of real and imaginary numbers to 0. r is for real part and i for imaginary part of complex number
ProblemSolution(int r = 0, int i =0) {
real = r; imag = i; }
/* print() method that displays real and imaginary part in output of the sum of complex numbers */
void print(){
//prints real and imaginary part of complex number with a space between //them
cout<<real<<" "<<imag;}
// computes the sum of complex numbers using operator overloading
ProblemSolution operator + (ProblemSolution const &P){ //pass by ref
ProblemSolution sum; // object of ProblemSolution
sum.real = real + P.real; // adds the real part of the complex nos.
sum.imag = imag + P.imag; //adds imaginary parts of complex nos.
//returns the resulting object
return sum; } //returns the sum of complex numbers
}; //end of the class ProblemSolution
int main(){ //start of the main() function body
int real,imag; //declare variables for real and imaginary part of complex nos
//reads values of real and imaginary part of first input complex no.1
cin>>real>>imag;
//creates object problemSolution1 for first complex number
ProblemSolution problemSolution1(real, imag); //creates object
//reads values of real and imaginary part of first input complex no.2
cin>>real>>imag;
//creates object problemSolution2 for second complex number
ProblemSolution problemSolution2(real,imag);
//creates object problemSolution2 to store the addition of two complex nos.
ProblemSolution problemSolution3 = problemSolution1 + problemSolution2;
problemSolution3.print();} //calls print() method to display the result of the //sum with real and imaginary part of the sum displayed with a space
Explanation:
The program is well explained in the comments mentioned with each statement of the program. The program has a class named ProblemSolution which has two data members real and imag to hold the values for the real and imaginary parts of the complex number. A default constructor ProblemSolution() which initializes an the objects for complex numbers 1 and 2 automatically when they are created.
ProblemSolution operator + (ProblemSolution const &P) is the operator overloading function. This performs the overloading of a binary operator + operating on two operands. This is used here to add two complex numbers. In order to use a binary operator one of the operands should be passed as argument to the operator function. Here one argument const &P is passed. This is call by reference. Object sum is created to add the two complex numbers with real and imaginary parts and then the resulting object which is the sum of these two complex numbers is returned.
In the main() method, three objects of type ProblemSolution are created and user is prompted to enter real and imaginary parts for two complex numbers. These are stored in objects problemSolution1 and problemSolution2. Then statement ProblemSolution problemSolution3 = problemSolution1 + problemSolution2; creates another object problemSolution3 to hold the result of the addition. When this statement is executed it invokes the operator function ProblemSolution operator + (ProblemSolution const &P). This function returns the resultant complex number (object) to main() function and print() function is called which is used to display the output of the addition.
