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Zinaida [17]
3 years ago
7

What should we do to prevent software piracy?

Computers and Technology
1 answer:
frozen [14]3 years ago
7 0

Answer:

1. Read the End User License Agreement (EULA) for each software product you purchase.

2. Purchase CD software only from reputable resellers.

3. Purchase software downloads directly from the manufacturer's website.

4. Register your software to prevent others from attempting to install your software on their computers.

5. Report piracy if you discover that software you purchased is not authentic or if you suspect that an online reseller or retail establishment is selling counterfeit software.

Link: https://www.techwalla.com/articles/how-to-stop-software-piracy

-Please mark as brainliest!- Thanks!

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Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
3 years ago
How to learn python ?
laila [671]

Answer:

https://www.python.org/about/gettingstarted/

Explanation:

its a site i used

7 0
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What is a fixed expense<br> everfi
Gelneren [198K]

Answer:

A fixed expense is an expense that has a constant total expense value (the total amount of the fixed expense) that remains the same (does not change) when there is a change in the number being managed, manufactured, or sold

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Explanation:

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To create a cover letter to send to potenial employers alone with a resume what software program should you use
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3 0
3 years ago
in java how do i Write a method named isEven that accepts an int argument. The method should return true if the argument is even
Veseljchak [2.6K]
<h2>Answer:</h2><h2>============================================</h2>

//Class header definition

public class TestEven {

   

   //Method main to test the method isEven

   public static void main(String args[ ] ) {

       

       //Test the method isEven using numbers 5 and 6 as arguments

       System.out.println(isEven(5));

       System.out.println(isEven(6));

     

   }

   

   //Method isEven

   //Method has a return type of boolean since it returns true or false.

   //Method has an int parameter

   public static boolean isEven(int number){

       //A number is even if its modulus with 2 gives zero

      if (number % 2 == 0){

           return true;

       }

       

       //Otherwise, the number is odd

       return false;

   }

}

====================================================

<h2>Sample Output:</h2>

=========================================================

false

true

==========================================================

<h2>Explanation:</h2>

The above code has been written in Java. It contains comments explaining every part of the code. Please go through the comments in the code.

A sample output has also been provided. You can save the code as TestEven.java and run it on your machine.

3 0
3 years ago
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